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A works twice as fast as B. If two can together complete a bit of work in 12 days, then B alone can do it in:
  • a)
    24 days
  • b)
    27 days
  • c)
    36 days
  • d)
    48 days
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A works twice as fast as B. If two can together complete a bit of work...
Given: A works twice as fast as B.
Let the time taken by B alone be x days
Therefore, the time taken by A alone will be x/2 days (since A works twice as fast as B)

Together, they can complete a bit of work in 12 days.
Let the total work be 1 unit.
Therefore, in 1 day, together they can complete 1/12th of the work.

Calculation:

Let's calculate the amount of work done by A and B in 1 day.
A can complete 1/x/2 = 2/x of the work in 1 day.
B can complete 1/x of the work in 1 day.

Together, they can complete 2/x + 1/x = 3/x of the work in 1 day.

As per the given condition, they complete 1 unit of work in 12 days.
Therefore, the amount of work done by them in 1 day is 1/12th of the total work.

Equating the two values of work done in 1 day, we get:

3/x = 1/12

Solving for x, we get:

x = 36

Therefore, B alone can complete the work in 36 days. Hence, option C is the correct answer.
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Community Answer
A works twice as fast as B. If two can together complete a bit of work...
Let B's 1 day work =x.
Then , A's 1 day's work=2x
X+2x=1/12
⇒ 3x=1/12
⇒ x=1/36.
B's 1 day work=1/36.
Hence B alone can finish the work in 36 days.
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A works twice as fast as B. If two can together complete a bit of work in 12 days, then B alone can do it in:a)24 daysb)27 daysc)36 daysd)48 daysCorrect answer is option 'C'. Can you explain this answer?
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