What will be the output of the following C++ code? #include using namespace std; int main() { char arr[20]; int i; for(i = 0; i

Question

What will be the output of the following C++ code?

#include <iostream>
using namespace std;
int main()
{
char arr[20];
int i;
for(i = 0; i < 10; i++)
*(arr + i) = 65 + i;
*(arr + i) = '\0';
cout << arr;
return(0);
}

a)
ABCDEFGHIJ
b)
AAAAAAAAAA
c)
JJJJJJJJ
d)
AAAAAAJJJJ

Correct answer is option 'A'. Can you explain this answer?

Answer

Each time we are assigning 65 + i. In first iteration i = 0 and 65 is assigned. So it will print from A to J.
$ g++ point1.cpp
$ a.out
ABCDEFGHIJ

Answer

Explanation:

The given C++ code initializes an array 'arr' with characters from 'A' to 'J' and then adds a null character '\0' at the end to signify the end of the string. Finally, it prints out the contents of the array.

Step-by-Step Explanation:

- Array Initialization:
- The for loop in the code iterates from 0 to 9 and assigns characters from 'A' to 'J' to successive elements of the array 'arr' using pointer arithmetic.
- After the loop completes, the array 'arr' contains the characters 'A' to 'J' at indices 0 to 9.

- Adding Null Terminator:
- After the loop finishes, the code adds a null character '\0' at the 10th index of the array 'arr' to terminate the string.

- Output:
- When the array 'arr' is printed using cout, it will output the contents of the array starting from index 0 until the null character is encountered.
- In this case, the output will be 'ABCDEFGHIJ' as the null character indicates the end of the string.

Therefore, the correct output of the given C++ code is option 'A' - 'ABCDEFGHIJ'.

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