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If Young's double slit experiment of light, interference is performed in water, which one of the following is correct?
- a)Fringe width will decrease.
- b)Fringe width will increase.
- c)There will be no fringe.
- d)Fringe width will remain unchanged.
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If Youngs double slit experiment of light, interference is performed i...
Interference of Light in Water
Interference of light is a phenomenon that occurs when two or more waves of light interact with each other. Young's double-slit experiment is a classic demonstration of interference, where a beam of light is passed through two parallel slits, creating an interference pattern on a screen behind them.
When this experiment is performed in water, there are several changes that occur due to the difference in the refractive index of water compared to air.
Fringe Width
The fringe width in Young's double-slit experiment is given by the equation:
w = λD/d
Where w is the fringe width, λ is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the slits.
In water, the refractive index is higher than air, which means that the wavelength of light is shorter. This results in a decrease in the fringe width. Therefore, option A is incorrect.
Interference Pattern
The interference pattern in water will still be visible, but it will be different than the pattern in air. The pattern will be shifted, and the fringes will be closer together. This is because the path length of the light waves is reduced due to the increased refractive index of water. Therefore, option C is incorrect.
Conclusion
In conclusion, when Young's double-slit experiment is performed in water, the fringe width will decrease, and the interference pattern will be shifted and closer together. Therefore, option B is the correct answer.
Interference of light is a phenomenon that occurs when two or more waves of light interact with each other. Young's double-slit experiment is a classic demonstration of interference, where a beam of light is passed through two parallel slits, creating an interference pattern on a screen behind them.
When this experiment is performed in water, there are several changes that occur due to the difference in the refractive index of water compared to air.
Fringe Width
The fringe width in Young's double-slit experiment is given by the equation:
w = λD/d
Where w is the fringe width, λ is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the slits.
In water, the refractive index is higher than air, which means that the wavelength of light is shorter. This results in a decrease in the fringe width. Therefore, option A is incorrect.
Interference Pattern
The interference pattern in water will still be visible, but it will be different than the pattern in air. The pattern will be shifted, and the fringes will be closer together. This is because the path length of the light waves is reduced due to the increased refractive index of water. Therefore, option C is incorrect.
Conclusion
In conclusion, when Young's double-slit experiment is performed in water, the fringe width will decrease, and the interference pattern will be shifted and closer together. Therefore, option B is the correct answer.
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If Youngs double slit experiment of light, interference is performed in water, which one of the following is correct?a)Fringe width will decrease.b)Fringe width will increase.c)There will be no fringe.d)Fringe width will remain unchanged.Correct answer is option 'B'. Can you explain this answer?
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If Youngs double slit experiment of light, interference is performed in water, which one of the following is correct?a)Fringe width will decrease.b)Fringe width will increase.c)There will be no fringe.d)Fringe width will remain unchanged.Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If Youngs double slit experiment of light, interference is performed in water, which one of the following is correct?a)Fringe width will decrease.b)Fringe width will increase.c)There will be no fringe.d)Fringe width will remain unchanged.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If Youngs double slit experiment of light, interference is performed in water, which one of the following is correct?a)Fringe width will decrease.b)Fringe width will increase.c)There will be no fringe.d)Fringe width will remain unchanged.Correct answer is option 'B'. Can you explain this answer?.
If Youngs double slit experiment of light, interference is performed in water, which one of the following is correct?a)Fringe width will decrease.b)Fringe width will increase.c)There will be no fringe.d)Fringe width will remain unchanged.Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If Youngs double slit experiment of light, interference is performed in water, which one of the following is correct?a)Fringe width will decrease.b)Fringe width will increase.c)There will be no fringe.d)Fringe width will remain unchanged.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If Youngs double slit experiment of light, interference is performed in water, which one of the following is correct?a)Fringe width will decrease.b)Fringe width will increase.c)There will be no fringe.d)Fringe width will remain unchanged.Correct answer is option 'B'. Can you explain this answer?.
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