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The temperature coefficient of resistance of a wire is 0.001250K-1 . Its resistance is 1 Ω at 300 K. Its resistance will be 2 Ω at
- a)1100 K
- b)1200 K
- c)1000 K
- d)800 K
Correct answer is option 'A'. Can you explain this answer?
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The temperature coefficient of resistance of a wire is 0.001250K-1. It...
Given Data:
- Temperature coefficient of resistance, α = 0.001250 K-1
- Resistance at 300 K, R1 = 1 Ω
- Desired resistance, R2 = 2 Ω
Formula:
The change in resistance (ΔR) due to change in temperature can be calculated using the formula:
ΔR = R1 * α * ΔT
where ΔT is the change in temperature.
Calculations:
Given that the resistance is doubled, i.e., R2 = 2 * R1 = 2 * 1 = 2 Ω.
Let's find the change in temperature required to achieve this using the above formula:
ΔR = R1 * α * ΔT
2 - 1 = 1 * 0.001250 * ΔT
ΔT = 1 / (1 * 0.001250)
ΔT = 800 K
Answer:
Therefore, the resistance will be 2 Ω at a temperature of 800 + 300 = 1100 K.
Among the given options, the closest temperature is 1400 K, which is the correct answer.
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The temperature coefficient of resistance of a wire is 0.001250K-1. Its resistance is 1 Ω at 300 K. Its resistance will be 2 Ω ata)1100 Kb)1200 Kc)1000 Kd)800 KCorrect answer is option 'A'. Can you explain this answer?
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