IIT JAM Exam > IIT JAM Questions > A sample of an ideal gas is taken through the...
Start Learning for Free
A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a .
? Related: Zeroth & First Law of Thermodynamics
Most Upvoted Answer
A sample of an ideal gas is taken through the cyclic process “abcd ” a...
Zeroth Law of Thermodynamics
The zeroth law of thermodynamics states that if two systems are each in thermal equilibrium with a third system, then they are in thermal equilibrium with each other. This law establishes the concept of temperature and allows us to define a temperature scale.
First Law of Thermodynamics
The first law of thermodynamics, also known as the law of energy conservation, states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system. Mathematically, it is represented as ΔU = Q - W, where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.
Analysis of the Cyclic Process
- Internal energy at point a: Ua = 1500 J
- Heat absorbed during ab: Qab = 50 J
- Heat rejected during ca: Qca = 70 J
- Work done during bc: Wbc = -40 J (negative because work is done on the gas)
- Internal energy at point b: Ub = Ua + Qab + Wbc = 1500 J + 50 J - 40 J = 1510 J
- Internal energy at point c: Uc = Ub + Qbc = 1510 J (no heat transfer during bc)
Therefore, the internal energy of the gas at point b is 1510 J and at point c is also 1510 J. This analysis follows the first law of thermodynamics, which states that the change in internal energy is equal to the heat added to the system minus the work done by the system.
The zeroth law of thermodynamics states that if two systems are each in thermal equilibrium with a third system, then they are in thermal equilibrium with each other. This law establishes the concept of temperature and allows us to define a temperature scale.
First Law of Thermodynamics
The first law of thermodynamics, also known as the law of energy conservation, states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system. Mathematically, it is represented as ΔU = Q - W, where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.
Analysis of the Cyclic Process
- Internal energy at point a: Ua = 1500 J
- Heat absorbed during ab: Qab = 50 J
- Heat rejected during ca: Qca = 70 J
- Work done during bc: Wbc = -40 J (negative because work is done on the gas)
- Internal energy at point b: Ub = Ua + Qab + Wbc = 1500 J + 50 J - 40 J = 1510 J
- Internal energy at point c: Uc = Ub + Qbc = 1510 J (no heat transfer during bc)
Therefore, the internal energy of the gas at point b is 1510 J and at point c is also 1510 J. This analysis follows the first law of thermodynamics, which states that the change in internal energy is equal to the heat added to the system minus the work done by the system.
|
Explore Courses for IIT JAM exam
|
|
Similar IIT JAM Doubts
A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics?
Question Description
A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics?.
A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics?.
Solutions for A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics? in English & in Hindi are available as part of our courses for IIT JAM.
Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
Here you can find the meaning of A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics? defined & explained in the simplest way possible. Besides giving the explanation of
A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics?, a detailed solution for A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics? has been provided alongside types of A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics? theory, EduRev gives you an
ample number of questions to practice A sample of an ideal gas is taken through the cyclic process “abcd ” as shown in figure. It absorbed 50Jof heat during part ab, no heat during bc and reject 70J of heat during ca, 40J of work is done on the gas during part bc .(a) Find the internal energy of the gas at b and c if it is 1500 J at a . Related: Zeroth & First Law of Thermodynamics? tests, examples and also practice IIT JAM tests.
|
|
Explore Courses for IIT JAM exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup