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Let f be a function from a set A to a set B, g a function from B to C, and h a function from A to C, such that h(a) = g(f(a)) for all a ∈ A. Which of the following statements is always true for all such functions f and g?  
  • a)
    g is onto => h is onto
  • b)
    h is onto => f is onto
  • c)
    h is onto => g is onto
  • d)
    h is onto => f and g are ont
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Let f be a function from a set A to a set B, g a function from B to C,...
Explanation:

To prove that the statement "h is onto = g is onto" is always true for all functions f and g, we need to show that if h is onto, then g is onto, and vice versa.

Proof:

1. Suppose h is onto. This means that for every element c in set C, there exists an element a in set A such that h(a) = c.
2. Let's consider an arbitrary element c in set C. Since h is onto, there exists an element a in set A such that h(a) = c.
3. According to the definition of h, we have h(a) = g(f(a)). So, c = g(f(a)).
4. This implies that for every element c in set C, there exists an element b = f(a) in set B such that g(b) = c.
5. Therefore, g is onto.

Proof (continued):

1. Suppose g is onto. This means that for every element c in set C, there exists an element b in set B such that g(b) = c.
2. Let's consider an arbitrary element c in set C. Since g is onto, there exists an element b in set B such that g(b) = c.
3. According to the definition of g, there exists an element a = f^(-1)(b) in set A such that f(a) = b.
4. This implies that for every element c in set C, there exists an element a = f^(-1)(b) in set A such that h(a) = g(f(a)) = g(b) = c.
5. Therefore, h is onto.

Conclusion:

From the two proofs above, we can conclude that if h is onto, then g is onto, and vice versa. Therefore, the statement "h is onto = g is onto" is always true for all functions f and g.
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Let f be a function from a set A to a set B, g a function from B to C, and h a function from A to C, such that h(a) = g(f(a)) for all a A. Which of the following statements is always true for all such functions f and g? a)g is onto = h is ontob)h is onto = f is ontoc)h is onto = g is ontod)h is onto = f and g are ontCorrect answer is option 'C'. Can you explain this answer?
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