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If x:y= 3:4 the value of x²y xy²:x³ y³ is?
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If x:y= 3:4 the value of x²y xy²:x³ y³ is?
Solution:

Given, x:y= 3:4

Let x = 3k and y = 4k (where k is a constant)

Finding the value of x²y:

x²y = (3k)²(4k) = 36k³

Finding the value of xy²:

xy² = (3k)(4k)² = 48k³

Finding the value of x³ y³:

x³ y³ = (3k)³(4k)³ = 1728k⁶

Now, we need to simplify the expressions in such a way that we can find their ratios.

Simplifying x²y and xy²:

x²y/xy² = (36k³)/(48k³) = 3/4

Simplifying x²y and x³ y³:

x²y/x³ y³ = (36k³)/(1728k⁶) = 1/48

Therefore, the value of x²y : xy² : x³ y³ is 3:4:48.

Hence, the solution.
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If x:y= 3:4 the value of x²y xy²:x³ y³ is?
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