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Select the correct option for decreasing order of number of atom 1) 2gm of hydrogen 2)16 gm of sulphur 3) 4gm of oxygen 4)31gm of phosphorus?
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Select the correct option for decreasing order of number of atom 1) 2g...
Decreasing order of number of atoms:
1. 16gm of sulphur - Sulphur has an atomic mass of 32u and 16gm of sulphur contains 0.5 moles of sulphur atoms. Therefore, the number of sulphur atoms present in 16gm of sulphur is 0.5 x Avogadro's number = 3.01 x 10^23 atoms.
2. 4gm of oxygen - Oxygen has an atomic mass of 16u and 4gm of oxygen contains 0.25 moles of oxygen atoms. Therefore, the number of oxygen atoms present in 4gm of oxygen is 0.25 x Avogadro's number = 1.51 x 10^23 atoms.
3. 31gm of phosphorus - Phosphorus has an atomic mass of 31u and 31gm of phosphorus contains 1 mole of phosphorus atoms. Therefore, the number of phosphorus atoms present in 31gm of phosphorus is Avogadro's number = 6.022 x 10^23 atoms.
4. 2gm of hydrogen - Hydrogen has an atomic mass of 1u and 2gm of hydrogen contains 2 moles of hydrogen atoms. Therefore, the number of hydrogen atoms present in 2gm of hydrogen is 2 x Avogadro's number = 1.2044 x 10^24 atoms.
Explanation:
The number of atoms present in a substance is directly proportional to the amount of substance present. Therefore, to determine the decreasing order of number of atoms, we need to calculate the number of moles of atoms in each substance and then multiply it by Avogadro's number (6.022 x 10^23 atoms per mole).
Sulphur and oxygen have relatively large atomic masses compared to phosphorus and hydrogen, so even though they have less mass, they still contain more atoms due to their smaller atomic mass. Therefore, sulphur and oxygen have more atoms than phosphorus and hydrogen.
Phosphorus contains one mole of atoms, which is the same as Avogadro's number. Hydrogen has the least atomic mass, but it contains the most number of atoms due to its small atomic mass and large amount of substance present.
1. 16gm of sulphur - Sulphur has an atomic mass of 32u and 16gm of sulphur contains 0.5 moles of sulphur atoms. Therefore, the number of sulphur atoms present in 16gm of sulphur is 0.5 x Avogadro's number = 3.01 x 10^23 atoms.
2. 4gm of oxygen - Oxygen has an atomic mass of 16u and 4gm of oxygen contains 0.25 moles of oxygen atoms. Therefore, the number of oxygen atoms present in 4gm of oxygen is 0.25 x Avogadro's number = 1.51 x 10^23 atoms.
3. 31gm of phosphorus - Phosphorus has an atomic mass of 31u and 31gm of phosphorus contains 1 mole of phosphorus atoms. Therefore, the number of phosphorus atoms present in 31gm of phosphorus is Avogadro's number = 6.022 x 10^23 atoms.
4. 2gm of hydrogen - Hydrogen has an atomic mass of 1u and 2gm of hydrogen contains 2 moles of hydrogen atoms. Therefore, the number of hydrogen atoms present in 2gm of hydrogen is 2 x Avogadro's number = 1.2044 x 10^24 atoms.
Explanation:
The number of atoms present in a substance is directly proportional to the amount of substance present. Therefore, to determine the decreasing order of number of atoms, we need to calculate the number of moles of atoms in each substance and then multiply it by Avogadro's number (6.022 x 10^23 atoms per mole).
Sulphur and oxygen have relatively large atomic masses compared to phosphorus and hydrogen, so even though they have less mass, they still contain more atoms due to their smaller atomic mass. Therefore, sulphur and oxygen have more atoms than phosphorus and hydrogen.
Phosphorus contains one mole of atoms, which is the same as Avogadro's number. Hydrogen has the least atomic mass, but it contains the most number of atoms due to its small atomic mass and large amount of substance present.
Community Answer
Select the correct option for decreasing order of number of atom 1) 2g...
2gm of hydrogen contains 2×Na no.of atoms of hydrogen =1.2044×10^24
16gm of Sulphur contains 1×Na no.of atoms of Sulphur =6.022×10^23
4gm of oxygen contains 0.5 Na no.of atoms of oxygen =3.011×10^23
31 gm of phosphorus contains 1 Na atoms = 6.022×10^23
Decreasing order is
1》2~4》3
16gm of Sulphur contains 1×Na no.of atoms of Sulphur =6.022×10^23
4gm of oxygen contains 0.5 Na no.of atoms of oxygen =3.011×10^23
31 gm of phosphorus contains 1 Na atoms = 6.022×10^23
Decreasing order is
1》2~4》3
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Select the correct option for decreasing order of number of atom 1) 2gm of hydrogen 2)16 gm of sulphur 3) 4gm of oxygen 4)31gm of phosphorus?
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Select the correct option for decreasing order of number of atom 1) 2gm of hydrogen 2)16 gm of sulphur 3) 4gm of oxygen 4)31gm of phosphorus? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Select the correct option for decreasing order of number of atom 1) 2gm of hydrogen 2)16 gm of sulphur 3) 4gm of oxygen 4)31gm of phosphorus? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Select the correct option for decreasing order of number of atom 1) 2gm of hydrogen 2)16 gm of sulphur 3) 4gm of oxygen 4)31gm of phosphorus?.
Select the correct option for decreasing order of number of atom 1) 2gm of hydrogen 2)16 gm of sulphur 3) 4gm of oxygen 4)31gm of phosphorus? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Select the correct option for decreasing order of number of atom 1) 2gm of hydrogen 2)16 gm of sulphur 3) 4gm of oxygen 4)31gm of phosphorus? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Select the correct option for decreasing order of number of atom 1) 2gm of hydrogen 2)16 gm of sulphur 3) 4gm of oxygen 4)31gm of phosphorus?.
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