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Can you explain the answer of this question below:
A carboxylic acid is converted into its anhydride using
- A:thionyl chloride
- B:sulphur chloride
- C:sulphuric acid
- D:Phosphorus pentaoxide
The answer is d.
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Can you explain the answer of this question below:A carboxylic acid is...
Conversion of Carboxylic Acid to Anhydride using Phosphorus Pentoxide
Carboxylic acids can be converted into their corresponding anhydrides by using dehydrating agents. The most commonly used dehydrating agents for this conversion are phosphorus pentoxide (P2O5), thionyl chloride (SOCl2), and phosphorus oxychloride (POCl3). Among these, P2O5 is the most commonly used dehydrating agent.
Steps involved in the conversion of carboxylic acid to anhydride using P2O5:
1. Preparation of the mixture
The carboxylic acid is mixed with P2O5 in a 1:1 molar ratio. The mixture is then heated to a temperature of around 150-200°C.
2. Elimination of water
When the mixture is heated, P2O5 acts as a dehydrating agent and eliminates a molecule of water from the carboxylic acid. This forms an intermediate acid anhydride.
RCOOH + P2O5 → RCOOP(O)OR + H2O
3. Formation of anhydride
The intermediate acid anhydride, formed by the elimination of water, further reacts with the remaining carboxylic acid to form the final anhydride.
RCOOP(O)OR + RCOOH → RCOOCOR + H2O
The final product formed is an anhydride of the original carboxylic acid.
Advantages of using P2O5 as a dehydrating agent:
1. High yield: The conversion using P2O5 gives a high yield of the anhydride.
2. Mild conditions: The reaction can be carried out at relatively mild conditions of around 150-200°C.
3. Cost-effective: P2O5 is a cost-effective dehydrating agent compared to other reagents like POCl3 and SOCl2.
Hence, the correct option for the given question is D, i.e., Phosphorus pentoxide.
Carboxylic acids can be converted into their corresponding anhydrides by using dehydrating agents. The most commonly used dehydrating agents for this conversion are phosphorus pentoxide (P2O5), thionyl chloride (SOCl2), and phosphorus oxychloride (POCl3). Among these, P2O5 is the most commonly used dehydrating agent.
Steps involved in the conversion of carboxylic acid to anhydride using P2O5:
1. Preparation of the mixture
The carboxylic acid is mixed with P2O5 in a 1:1 molar ratio. The mixture is then heated to a temperature of around 150-200°C.
2. Elimination of water
When the mixture is heated, P2O5 acts as a dehydrating agent and eliminates a molecule of water from the carboxylic acid. This forms an intermediate acid anhydride.
RCOOH + P2O5 → RCOOP(O)OR + H2O
3. Formation of anhydride
The intermediate acid anhydride, formed by the elimination of water, further reacts with the remaining carboxylic acid to form the final anhydride.
RCOOP(O)OR + RCOOH → RCOOCOR + H2O
The final product formed is an anhydride of the original carboxylic acid.
Advantages of using P2O5 as a dehydrating agent:
1. High yield: The conversion using P2O5 gives a high yield of the anhydride.
2. Mild conditions: The reaction can be carried out at relatively mild conditions of around 150-200°C.
3. Cost-effective: P2O5 is a cost-effective dehydrating agent compared to other reagents like POCl3 and SOCl2.
Hence, the correct option for the given question is D, i.e., Phosphorus pentoxide.
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Community Answer
Can you explain the answer of this question below:A carboxylic acid is...
P2O5 at high temperature is stronger dehydrating agent. H2SO4 will be difficult to separate so it is not used.
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Can you explain the answer of this question below:A carboxylic acid is converted into its anhydride usingA: thionyl chloride B: sulphur chloride C: sulphuric acid D: Phosphorus pentaoxide The answer is d.
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Can you explain the answer of this question below:A carboxylic acid is converted into its anhydride usingA: thionyl chloride B: sulphur chloride C: sulphuric acid D: Phosphorus pentaoxide The answer is d. for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Can you explain the answer of this question below:A carboxylic acid is converted into its anhydride usingA: thionyl chloride B: sulphur chloride C: sulphuric acid D: Phosphorus pentaoxide The answer is d. covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:A carboxylic acid is converted into its anhydride usingA: thionyl chloride B: sulphur chloride C: sulphuric acid D: Phosphorus pentaoxide The answer is d..
Can you explain the answer of this question below:A carboxylic acid is converted into its anhydride usingA: thionyl chloride B: sulphur chloride C: sulphuric acid D: Phosphorus pentaoxide The answer is d. for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Can you explain the answer of this question below:A carboxylic acid is converted into its anhydride usingA: thionyl chloride B: sulphur chloride C: sulphuric acid D: Phosphorus pentaoxide The answer is d. covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:A carboxylic acid is converted into its anhydride usingA: thionyl chloride B: sulphur chloride C: sulphuric acid D: Phosphorus pentaoxide The answer is d..
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