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A ball is released from the top of a tower of height H meters. It take t second to reach the ground what is the position of the ball in t / 3 seconds?
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A ball is released from the top of a tower of height H meters. It take...
Position of the Ball in t/3 seconds
Position at t/3 seconds can be calculated by finding the distance covered by the ball in t/3 seconds.

Calculating the Distance Covered
When the ball is released from the top of the tower, it has an initial velocity of 0 m/s. Using the equation of motion, we can find the distance covered by the ball in t seconds:
s = ut + (1/2)at^2
Where:
s = distance covered
u = initial velocity (0 m/s)
a = acceleration due to gravity (-9.8 m/s^2)
t = time taken to reach the ground (t seconds)
Substitute the values into the equation:
s = 0 + (1/2)(-9.8)(t)^2
s = -4.9t^2
The distance covered by the ball in t seconds is -4.9t^2 meters.

Finding the Position at t/3 seconds
To find the position of the ball at t/3 seconds, we need to substitute t/3 into the equation:
s = -4.9(t/3)^2
s = -4.9(t^2/9)
s = -0.544t^2
Therefore, the position of the ball at t/3 seconds is -0.544t^2 meters from the top of the tower.
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A ball is released from the top of a tower of height H meters. It take t second to reach the ground what is the position of the ball in t / 3 seconds?
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