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From the top of a tower, a ball is thrown vertically upward which reaches the ground in 6 s. A second ball thrown vertically downward from the same position with the same speed reaches the ground in 1.5 s. A third ball released, from the rest from the same location, will reach the ground in ____ s.(In Integers)
Correct answer is '3'. Can you explain this answer?
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Most Upvoted Answer
From the top of a tower, a ball is thrown vertically upward which reac...
Solution:
Given:
Time taken by the first ball to reach the ground = 6 s
Time taken by the second ball to reach the ground = 1.5 s
Let's analyze each ball's motion separately to understand their behavior.
First Ball:
- The first ball is thrown vertically upward from the top of the tower.
- The motion of the ball is influenced by the gravitational force, which acts in the downward direction.
- As the ball moves upward, it slows down due to the gravitational force acting against its motion.
- At the highest point of its trajectory, the ball momentarily stops before starting to fall back down.
- The total time taken by the ball to reach the ground is 6 s.
Second Ball:
- The second ball is thrown vertically downward from the same position with the same speed as the first ball.
- The motion of the ball is solely influenced by the gravitational force, which acts in the downward direction.
- Since the ball is thrown downward, its initial velocity is negative.
- The ball accelerates due to gravity, and its speed increases as it falls.
- The total time taken by the ball to reach the ground is 1.5 s.
Third Ball:
- The third ball is released from rest from the same location.
- Since the ball is released from rest, its initial velocity is zero.
- The motion of the ball is solely influenced by the gravitational force, which acts in the downward direction.
- As the ball falls freely, it accelerates due to gravity.
- The time taken by the ball to reach the ground can be calculated using the equation:
t = sqrt((2h)/g)
where t is the time taken, h is the initial height, and g is the acceleration due to gravity.
- Since the initial height is the same as the height of the tower, the time taken by the third ball to reach the ground is 3 seconds.
Therefore, the third ball will reach the ground in 3 seconds.
Given:
Time taken by the first ball to reach the ground = 6 s
Time taken by the second ball to reach the ground = 1.5 s
Let's analyze each ball's motion separately to understand their behavior.
First Ball:
- The first ball is thrown vertically upward from the top of the tower.
- The motion of the ball is influenced by the gravitational force, which acts in the downward direction.
- As the ball moves upward, it slows down due to the gravitational force acting against its motion.
- At the highest point of its trajectory, the ball momentarily stops before starting to fall back down.
- The total time taken by the ball to reach the ground is 6 s.
Second Ball:
- The second ball is thrown vertically downward from the same position with the same speed as the first ball.
- The motion of the ball is solely influenced by the gravitational force, which acts in the downward direction.
- Since the ball is thrown downward, its initial velocity is negative.
- The ball accelerates due to gravity, and its speed increases as it falls.
- The total time taken by the ball to reach the ground is 1.5 s.
Third Ball:
- The third ball is released from rest from the same location.
- Since the ball is released from rest, its initial velocity is zero.
- The motion of the ball is solely influenced by the gravitational force, which acts in the downward direction.
- As the ball falls freely, it accelerates due to gravity.
- The time taken by the ball to reach the ground can be calculated using the equation:
t = sqrt((2h)/g)
where t is the time taken, h is the initial height, and g is the acceleration due to gravity.
- Since the initial height is the same as the height of the tower, the time taken by the third ball to reach the ground is 3 seconds.
Therefore, the third ball will reach the ground in 3 seconds.
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Community Answer
From the top of a tower, a ball is thrown vertically upward which reac...
Based on the situation,
Solving above equations
= 3 s
Solving above equations
= 3 s
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From the top of a tower, a ball is thrown vertically upward which reaches the ground in 6 s. A second ball thrown vertically downward from the same position with the same speed reaches the ground in 1.5 s. A third ball released, from the rest from the same location, will reach the ground in ____ s.(In Integers)Correct answer is '3'. Can you explain this answer?
Question Description
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