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A block of mass 2 kg is pushed against a rough vertical wall with a force of 30 N. coefficient of static friction being 0.5. Another upward vertical force of 15 N is applied on the block in a direction parallel to the wall. What is the acceleration of block (in m/s² )?
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A block of mass 2 kg is pushed against a rough vertical wall with a fo...
Given data:
Mass of the block (m) = 2 kg
Force applied against the wall (F1) = 30 N
Coefficient of static friction (μ) = 0.5
Upward vertical force applied (F2) = 15 N
Calculation:
1. Normal force (N):
The normal force is the force exerted by the wall on the block perpendicular to the surface of the wall. Since the block is pushed against the wall, the normal force will be equal to the weight of the block, which can be calculated using the formula:
N = mg
= 2 kg × 9.8 m/s²
= 19.6 N
2. Force of friction (Ff):
The force of friction between the block and the wall can be calculated using the formula:
Ff = μN
= 0.5 × 19.6 N
= 9.8 N
3. Net force (Fnet):
The net force acting on the block is the vector sum of the applied forces. In this case, the net force can be calculated as:
Fnet = F2 - Ff
= 15 N - 9.8 N
= 5.2 N (upward)
4. Acceleration (a):
Using Newton's second law of motion, we can calculate the acceleration of the block:
Fnet = ma
5.2 N = 2 kg × a
a = 5.2 N / 2 kg
a = 2.6 m/s²
Answer:
The acceleration of the block is 2.6 m/s².
Mass of the block (m) = 2 kg
Force applied against the wall (F1) = 30 N
Coefficient of static friction (μ) = 0.5
Upward vertical force applied (F2) = 15 N
Calculation:
1. Normal force (N):
The normal force is the force exerted by the wall on the block perpendicular to the surface of the wall. Since the block is pushed against the wall, the normal force will be equal to the weight of the block, which can be calculated using the formula:
N = mg
= 2 kg × 9.8 m/s²
= 19.6 N
2. Force of friction (Ff):
The force of friction between the block and the wall can be calculated using the formula:
Ff = μN
= 0.5 × 19.6 N
= 9.8 N
3. Net force (Fnet):
The net force acting on the block is the vector sum of the applied forces. In this case, the net force can be calculated as:
Fnet = F2 - Ff
= 15 N - 9.8 N
= 5.2 N (upward)
4. Acceleration (a):
Using Newton's second law of motion, we can calculate the acceleration of the block:
Fnet = ma
5.2 N = 2 kg × a
a = 5.2 N / 2 kg
a = 2.6 m/s²
Answer:
The acceleration of the block is 2.6 m/s².
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A block of mass 2 kg is pushed against a rough vertical wall with a force of 30 N. coefficient of static friction being 0.5. Another upward vertical force of 15 N is applied on the block in a direction parallel to the wall. What is the acceleration of block (in m/s² )?
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A block of mass 2 kg is pushed against a rough vertical wall with a force of 30 N. coefficient of static friction being 0.5. Another upward vertical force of 15 N is applied on the block in a direction parallel to the wall. What is the acceleration of block (in m/s² )? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A block of mass 2 kg is pushed against a rough vertical wall with a force of 30 N. coefficient of static friction being 0.5. Another upward vertical force of 15 N is applied on the block in a direction parallel to the wall. What is the acceleration of block (in m/s² )? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 2 kg is pushed against a rough vertical wall with a force of 30 N. coefficient of static friction being 0.5. Another upward vertical force of 15 N is applied on the block in a direction parallel to the wall. What is the acceleration of block (in m/s² )?.
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