The ratio of milk and water in a container is 5:23. Some amount of wat...
Given Information:
Ratio of milk and water in the container = 5:23
Quantity of mixture is increased by 25%
20% of the mixture is removed and replaced with pure milk
Solution:
Step 1: Find the initial quantity of mixture
Let the initial quantity of mixture be 5x + 23x = 28x.
Step 2: Increase in quantity of mixture
As the quantity of mixture is increased by 25%, the new quantity of mixture becomes:
28x + 25% of 28x = 28x + 7x = 35x.
Step 3: Remove and replace mixture
20% of the mixture is removed and replaced with pure milk. Therefore, the amount of mixture removed is:
20% of 35x = (20/100) × 35x = 7x.
After removing the mixture, the quantity of mixture left is:
35x - 7x = 28x.
Now, 20% of the mixture is replaced with pure milk. Therefore, the amount of mixture replaced with milk is:
20% of 28x = (20/100) × 28x = 5.6x.
Therefore, the amount of milk in the new mixture is:
5 + 5.6 = 10.6x.
And the amount of water in the new mixture is:
23x - 7x + 5.6x = 21.6x.
Step 4: Find the ratio of milk and water in the new mixture
The ratio of milk to water in the new mixture is:
10.6x : 21.6x = 53 : 108.
Final Answer:
The ratio of milk to water in the new mixture is 53:108.