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Question. The sum of the series 1/√3 1 3/√3 . to 18 terms is a.) 9841 (1 √3)/ √3 b.) 9841 c.) 9841/√3 d.) none of these?
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Question. The sum of the series 1/√3 1 3/√3 . to 18 terms is a.) ...
Solution:

Given series is 1/√3 1 3/√3 ...

Let a = 1/√3 and d = 2/√3

We have to find the sum of the series up to 18 terms.

Using the formula for the sum of n terms of an arithmetic series:

S = n/2 [2a + (n - 1)d]

Substituting the given values, we get:

S = 18/2 [2(1/√3) + (18 - 1)(2/√3)]

S = 9 [2/√3 + (17)(2/√3)]

S = 9 [2/√3 + 34/√3]

S = 9 (36/√3)

S = 324/√3

Multiplying the numerator and denominator by √3, we get:

S = (324√3)/3

S = 108√3

Thus, the sum of the series up to 18 terms is 108√3.

Therefore, the answer is d.) none of these, as none of the given options match the calculated answer.
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Question. The sum of the series 1/√3 1 3/√3 . to 18 terms is a.) 9841 (1 √3)/ √3 b.) 9841 c.) 9841/√3 d.) none of these?
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Question. The sum of the series 1/√3 1 3/√3 . to 18 terms is a.) 9841 (1 √3)/ √3 b.) 9841 c.) 9841/√3 d.) none of these? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Question. The sum of the series 1/√3 1 3/√3 . to 18 terms is a.) 9841 (1 √3)/ √3 b.) 9841 c.) 9841/√3 d.) none of these? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Question. The sum of the series 1/√3 1 3/√3 . to 18 terms is a.) 9841 (1 √3)/ √3 b.) 9841 c.) 9841/√3 d.) none of these?.
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