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An organic hydrocarbons A is ozonised and subsequently hydrolysed in the presence of zinc to produce compound B and compund C. B on treatment with dil.KOH produced 3-hydroxybutanal where C heated with 50% con. KOH produced two products methanol and potassium methanoate.?
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An organic hydrocarbons A is ozonised and subsequently hydrolysed in t...
Introduction:
In this reaction, organic hydrocarbon A undergoes ozonolysis followed by hydrolysis in the presence of zinc. This results in the formation of two compounds, B and C. Compound B, upon treatment with dilute KOH, produces 3-hydroxybutanal. Compound C, when heated with 50% concentrated KOH, produces methanol and potassium methanoate. Let's discuss this reaction in detail.

Ozonolysis of A:
1. In ozonolysis, organic hydrocarbon A reacts with ozone (O3) to form ozonide intermediates.
2. The ozonide intermediates are unstable and decompose to form aldehyde or ketone compounds.
3. In this case, the ozonolysis of A may result in the formation of an aldehyde or ketone, which is compound B.

Hydrolysis of B:
1. Compound B, obtained from the ozonolysis of A, is then hydrolyzed in the presence of zinc.
2. Hydrolysis involves the reaction of a compound with water, resulting in the cleavage of bonds and the formation of new compounds.
3. In this reaction, hydrolysis of B may result in the formation of 3-hydroxybutanal.

Treatment of B with dilute KOH:
1. Compound B is further treated with dilute KOH (potassium hydroxide).
2. The reaction involves the addition of a hydroxide group (OH-) to the aldehyde group in compound B.
3. This addition reaction results in the formation of 3-hydroxybutanal.

Heating of C with 50% concentrated KOH:
1. Compound C, obtained from the ozonolysis and subsequent hydrolysis of A, is heated with 50% concentrated KOH (potassium hydroxide).
2. The concentrated KOH acts as a strong base and promotes the reaction.
3. The heating of C with concentrated KOH results in the formation of methanol and potassium methanoate.
4. The reaction involves the cleavage of the C-O bond in compound C, leading to the formation of methanol and potassium methanoate.

Conclusion:
In summary, the organic hydrocarbon A undergoes ozonolysis and subsequent hydrolysis to produce compounds B and C. Compound B, upon treatment with dilute KOH, forms 3-hydroxybutanal. Compound C, when heated with 50% concentrated KOH, forms methanol and potassium methanoate. This reaction sequence allows for the transformation of the starting hydrocarbon into different products with the help of ozone, water, zinc, and potassium hydroxide.
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An organic hydrocarbons A is ozonised and subsequently hydrolysed in the presence of zinc to produce compound B and compund C. B on treatment with dil.KOH produced 3-hydroxybutanal where C heated with 50% con. KOH produced two products methanol and potassium methanoate.?
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An organic hydrocarbons A is ozonised and subsequently hydrolysed in the presence of zinc to produce compound B and compund C. B on treatment with dil.KOH produced 3-hydroxybutanal where C heated with 50% con. KOH produced two products methanol and potassium methanoate.? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An organic hydrocarbons A is ozonised and subsequently hydrolysed in the presence of zinc to produce compound B and compund C. B on treatment with dil.KOH produced 3-hydroxybutanal where C heated with 50% con. KOH produced two products methanol and potassium methanoate.? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic hydrocarbons A is ozonised and subsequently hydrolysed in the presence of zinc to produce compound B and compund C. B on treatment with dil.KOH produced 3-hydroxybutanal where C heated with 50% con. KOH produced two products methanol and potassium methanoate.?.
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