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The liquid having specific gravity 0.85 flows through a pipe at a velocity of 2.5 m/sec and having discharge of 0.86 m³/sec calculate the diameter of the pipe if flow is considered to be laminar. I?
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The liquid having specific gravity 0.85 flows through a pipe at a velo...
**Given:**
Specific gravity of the liquid (S) = 0.85
Velocity of flow (V) = 2.5 m/sec
Discharge (Q) = 0.86 m³/sec

**Assumption:**
The flow is considered to be laminar.

**Formula:**
The formula to calculate the discharge (Q) in a laminar flow is given by:
Q = (π * d^2 * V) / 4

Where,
Q = Discharge
d = Diameter of the pipe
V = Velocity of flow

**Calculation:**
Rearranging the formula, we get:
d^2 = (4 * Q) / (π * V)

Substituting the given values:
d^2 = (4 * 0.86) / (π * 2.5)
d^2 = 1.088 / 7.85
d^2 = 0.1387
d ≈ √0.1387
d ≈ 0.3726 m

Therefore, the diameter of the pipe is approximately 0.3726 meters.
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The liquid having specific gravity 0.85 flows through a pipe at a velocity of 2.5 m/sec and having discharge of 0.86 m³/sec calculate the diameter of the pipe if flow is considered to be laminar. I?
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