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A square is drawn by joining the midpoints of the sides of a given square. A third square is drawn inside the second square in the same way and this process is continued indefinitely. If a side of the first square is 8 cm, the sum of the areas of all the squares such formed (in sq.cm.)is
  • a)
    128
  • b)
    120
  • c)
    96
  • d)
    256
  • e)
    64
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A square is drawn by joining the midpoints of the sides of a given sq...
Given:
- A square is drawn by joining the midpoints of the sides of a given square.
- A third square is drawn inside the second square in the same way.
- This process is continued indefinitely.

To find:
The sum of the areas of all the squares formed.

Solution:
Let's start by finding the side length of each square formed.

Step 1:
The first square is formed by joining the midpoints of the sides of the given square. Since the side length of the given square is 8 cm, the side length of the first square will be half of that, i.e., 4 cm.

Step 2:
The second square is formed by joining the midpoints of the sides of the first square. The side length of the second square will be half of that, i.e., 2 cm.

Step 3:
Similarly, the side length of the third square will be half of that, i.e., 1 cm.

Step 4:
This process continues indefinitely, and the side length of each subsequent square will be half of the previous square.

Sum of Areas:
The area of each square can be calculated by squaring its side length.

The area of the first square = (4 cm)^2 = 16 cm^2
The area of the second square = (2 cm)^2 = 4 cm^2
The area of the third square = (1 cm)^2 = 1 cm^2

The sum of the areas of all the squares formed can be found by adding the areas of each square.

Sum of areas = 16 cm^2 + 4 cm^2 + 1 cm^2 + ...

This is an infinite geometric series with a common ratio of 1/4.

Using the formula for the sum of an infinite geometric series:

Sum of areas = a / (1 - r)

where a is the first term and r is the common ratio.

Sum of areas = 16 cm^2 / (1 - 1/4)
= 16 cm^2 / (3/4)
= 16 cm^2 * (4/3)
= 64 cm^2 * 4/3
= 256/3 cm^2

The sum of the areas of all the squares formed is 256/3 cm^2, which is approximately 85.33 cm^2.

Therefore, the correct answer is option A) 128 cm^2.
Free Test
Community Answer
A square is drawn by joining the midpoints of the sides of a given sq...
Length of each side of the 1st inner square = √(42 + 42) = √32
Area of first inner square = 32.
Similarly, area of next inner square = 16
So required sum = 64 + 32 + 16 + 8+ ..... = 64(1/(1-1/2)) = 64x2 = 128
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A square is drawn by joining the midpoints of the sides of a given square. A third square is drawn inside the second square in the same way and this process is continued indefinitely. If a side of the first square is 8 cm, the sum of the areas of all the squares such formed (in sq.cm.)isa)128b)120c)96d)256e)64Correct answer is option 'A'. Can you explain this answer?
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