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The upper arms of the porter governor are pivoted on the axis of rotation. Their length being 30cm. The lower arms are pivoted on the sleeve at a distance of 3 cm from the axis. Their length being 27cm. Mass of each ball is 6kg and the sleeve mass is 50kg. Determine the equilibrium speed for a radius of rotation of 17cm and also the effort and power for 1 % change of speed.?
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The upper arms of the porter governor are pivoted on the axis of rotat...
Equilibrium Speed Calculation:
- First, calculate the moment of inertia of the system. The moment of inertia of each ball is I = m*r^2, where m is the mass of the ball (6kg) and r is the distance from the axis of rotation (17cm). The moment of inertia of each ball is 6*0.17^2 = 0.1734 kg*m^2.
- The moment of inertia of the sleeve can be calculated using the parallel axis theorem. I_sleeve = m_sleeve*r_sleeve^2 + m_sleeve*d^2, where m_sleeve is the mass of the sleeve (50kg), r_sleeve is the distance from the axis of rotation (17cm), and d is the distance between the axis and the sleeve pivot (3cm). The moment of inertia of the sleeve is 50*0.17^2 + 50*0.03^2 = 1.618 kg*m^2.
- The total moment of inertia of the system is the sum of the moments of inertia of the balls and the sleeve. I_total = 2*I_ball + I_sleeve = 2*0.1734 + 1.618 = 1.9648 kg*m^2.
- Next, calculate the gravitational force acting on the balls. F_gravity = m*g, where m is the mass of the ball (6kg) and g is the acceleration due to gravity (9.81 m/s^2). F_gravity = 6*9.81 = 58.86 N.
- The equilibrium speed can be calculated using the equation V = sqrt(2*g*h/I_total), where h is the height of the balls above the equilibrium position (0 since they are at the equilibrium position). Plugging in the values, V = sqrt(2*9.81*0/1.9648) = 0 m/s.

Effort and Power Calculation:
- The effort required to change the speed by 1% can be calculated using the equation Effort = I_total*(1-V_new/V_old), where V_old is the initial speed (0 m/s) and V_new is the new speed after a 1% change. Assuming the new speed is 1% of the equilibrium speed, V_new = 0.01*0 = 0 m/s. Effort = 1.9648*(1-0/0) = 0 N.
- The power required to change the speed can be calculated using the equation Power = Effort*V_new = 0*0 = 0 W.
Therefore, the equilibrium speed for a radius of rotation of 17cm is 0 m/s, and the effort and power required for a 1% change of speed are 0 N and 0 W, respectively.
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The upper arms of the porter governor are pivoted on the axis of rotation. Their length being 30cm. The lower arms are pivoted on the sleeve at a distance of 3 cm from the axis. Their length being 27cm. Mass of each ball is 6kg and the sleeve mass is 50kg. Determine the equilibrium speed for a radius of rotation of 17cm and also the effort and power for 1 % change of speed.?
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The upper arms of the porter governor are pivoted on the axis of rotation. Their length being 30cm. The lower arms are pivoted on the sleeve at a distance of 3 cm from the axis. Their length being 27cm. Mass of each ball is 6kg and the sleeve mass is 50kg. Determine the equilibrium speed for a radius of rotation of 17cm and also the effort and power for 1 % change of speed.? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The upper arms of the porter governor are pivoted on the axis of rotation. Their length being 30cm. The lower arms are pivoted on the sleeve at a distance of 3 cm from the axis. Their length being 27cm. Mass of each ball is 6kg and the sleeve mass is 50kg. Determine the equilibrium speed for a radius of rotation of 17cm and also the effort and power for 1 % change of speed.? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The upper arms of the porter governor are pivoted on the axis of rotation. Their length being 30cm. The lower arms are pivoted on the sleeve at a distance of 3 cm from the axis. Their length being 27cm. Mass of each ball is 6kg and the sleeve mass is 50kg. Determine the equilibrium speed for a radius of rotation of 17cm and also the effort and power for 1 % change of speed.?.
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