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If a charge is placed outside a closed surface, flux due to that charge inside the surface will be ________
- a)Positive
- b)May be positive or negative, depending on the nature of the charge
- c)Negative
- d)Zero
Correct answer is option 'D'. Can you explain this answer?
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If a charge is placed outside a closed surface, flux due to that charg...
Flux due to a charge outside a closed surface is zero because the electric field lines originating from the charge pass through the surface without intersecting or penetrating it. This can be explained using Gauss's law and the concept of electric flux.
Gauss's law states that the total electric flux through a closed surface is equal to the net charge enclosed by the surface divided by the permittivity of the medium. Mathematically, it can be written as:
Φ = Q/ε₀
Where Φ is the electric flux, Q is the net charge enclosed by the surface, and ε₀ is the permittivity of free space.
When a charge is placed outside a closed surface, the electric field lines originating from the charge extend indefinitely into space. These field lines are radial and symmetrically distributed around the charge.
Now, let's consider a closed surface that encloses the charge. Since the electric field lines are radial, they will intersect the surface perpendicularly. The number of electric field lines passing through the surface will be proportional to the charge enclosed by the surface.
Considering a Gaussian surface, which is a hypothetical closed surface, we can apply Gauss's law. Since the electric field lines pass through the surface without intersecting it, the flux through the surface will be zero. This is because the electric field lines are neither entering nor leaving the surface.
Therefore, the net charge enclosed by the surface will also be zero, as the electric field lines originating from the charge outside the surface do not contribute to the flux through the surface.
Hence, the flux due to a charge placed outside a closed surface is zero.
Gauss's law states that the total electric flux through a closed surface is equal to the net charge enclosed by the surface divided by the permittivity of the medium. Mathematically, it can be written as:
Φ = Q/ε₀
Where Φ is the electric flux, Q is the net charge enclosed by the surface, and ε₀ is the permittivity of free space.
When a charge is placed outside a closed surface, the electric field lines originating from the charge extend indefinitely into space. These field lines are radial and symmetrically distributed around the charge.
Now, let's consider a closed surface that encloses the charge. Since the electric field lines are radial, they will intersect the surface perpendicularly. The number of electric field lines passing through the surface will be proportional to the charge enclosed by the surface.
Considering a Gaussian surface, which is a hypothetical closed surface, we can apply Gauss's law. Since the electric field lines pass through the surface without intersecting it, the flux through the surface will be zero. This is because the electric field lines are neither entering nor leaving the surface.
Therefore, the net charge enclosed by the surface will also be zero, as the electric field lines originating from the charge outside the surface do not contribute to the flux through the surface.
Hence, the flux due to a charge placed outside a closed surface is zero.
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If a charge is placed outside a closed surface, flux due to that charg...
According to Gauss’s principle, if there is no charge bound inside a surface, net electric flux coming out of the surface will always be 0. In this case, the charge is kept outside the surface, so it will generate no field lines and hence no flux inside the surface. The situation will be the same if an electric dipole is placed inside a surface as the dipole has equal positive and negative charges; the total charge inside the surface becomes 0.
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If a charge is placed outside a closed surface, flux due to that charge inside the surface will be ________a)Positiveb)May be positive or negative, depending on the nature of the chargec)Negatived)ZeroCorrect answer is option 'D'. Can you explain this answer?
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