The electric field strength in an electromagnetic wave is 10 ^ 6 V / m The magnitude of magnetic field strength (in tesla) will be (1) 10 ^ 4 (2) 3 * 10 ^ 12 (3) 3.3 * 10 ^ - 4 (4) 3.3 * 10 ^ -3?

Question

Answer

Calculation of the Magnetic Field Strength:

The electric field strength (E) in an electromagnetic wave is given as 10^6 V/m. We need to find the magnitude of the magnetic field strength (B) in tesla.

Relationship between Electric and Magnetic Field Strengths:

In an electromagnetic wave, the electric and magnetic fields are interconnected and perpendicular to each other. The ratio between the magnitudes of the electric and magnetic field strengths is given by the speed of light (c) in a vacuum.

The speed of light (c) is approximately 3 × 10^8 m/s.

So, the ratio between E and B is given by:

E/B = c

Substituting the Values:

Given that E = 10^6 V/m, we can substitute this value in the equation:

10^6 V/m = B × 3 × 10^8 m/s

Simplifying this equation, we can find the value of B:

B = (10^6 V/m) / (3 × 10^8 m/s)

Now, let's simplify this expression further.

Simplification:

Dividing the numerator and denominator by 10^6, we get:

B = 1 / (3 × 10^2)

Simplifying further, we obtain:

B = 1 / 300

This can be written as:

B = 3.33 × 10^(-3)

Therefore, the magnitude of the magnetic field strength (B) in tesla is approximately 3.33 × 10^(-3) T.

Final Answer:

The correct option is (4) 3.3 × 10^(-3) T.

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