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In the question, two quantities I and II are given. You have to solve both the quantities to find the correct relation between Quantity-I and Quantity-II and choose the correct option.
Q. Quantity-I: A shopkeeper sold an article at 40% discount. Find the selling price of the article if its cost price and marked price are equal and there is a loss of Rs. 800 in the transaction?
Quantity-II: Karthick spends 80% of his income and saves Rs. 7200. Find the savings of Surya whose income is 20% more than that of Karthick and he spends 85% of his income?
  • a)
    Quantity-I > Quantity-II
  • b)
    Quantity-I < />
  • c)
    Quantity-I ≤ Quantity-II
  • d)
    Quantity-I = Quantity-II or No relation
  • e)
    Quantity-I ≥ Quantity-II
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In the question, two quantities I and II are given. You have to solve...
To solve this problem, let's solve each quantity one by one:

Quantity-I: A shopkeeper sold an article at a 40% discount. Find the selling price of the article if its cost price and marked price are equal and there is a loss of Rs. 800 in the transaction.

Let's assume the cost price of the article is x.
Since the cost price and marked price are equal, the marked price is also x.
The shopkeeper sold the article at a 40% discount, so the selling price is (100% - 40%) = 60% of the marked price.
Therefore, the selling price is 0.6x.

We are given that there is a loss of Rs. 800 in the transaction.
Loss = Cost Price - Selling Price
800 = x - 0.6x
800 = 0.4x
x = 800 / 0.4
x = 2000

So, the cost price of the article is Rs. 2000 and the selling price is 0.6 * 2000 = Rs. 1200.

Quantity-II: Karthick spends 80% of his income and saves Rs. 7200. Find the savings of Surya whose income is 20% more than that of Karthick and he spends 85% of his income.

Let's assume Karthick's income is y.
Karthick spends 80% of his income, so his savings are 20% of his income.
20% of y = Rs. 7200
0.2y = 7200
y = 7200 / 0.2
y = 36000

Surya's income is 20% more than Karthick's income, so Surya's income is (1 + 20%) = 1.2 times Karthick's income.
Surya's income = 1.2 * 36000 = 43200

Surya spends 85% of his income, so his savings are 15% of his income.
15% of 43200 = 0.15 * 43200 = Rs. 6480

Therefore, Surya's savings are Rs. 6480.

Comparison:

Quantity-I: Selling price = Rs. 1200
Quantity-II: Surya's savings = Rs. 6480

As Rs. 1200 < rs.="" 6480,="" we="" can="" conclude="" that="" quantity-i="" />< />

Therefore, the correct answer is option 'B' (Quantity-I < quantity-ii).="" />
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Community Answer
In the question, two quantities I and II are given. You have to solve...
Quantity I
Let the cost price of the article be Rs. x
According to the question,
0.40x = 800
x = Rs. 2000
Therefore, cost price of the article = Rs. 2000
Quantity II:
Let the income of Karthick be Rs. x
Therefore, 0.20x = 7200
Or, x = 7200/0.20 = Rs. 36000
Therefore, income of Surya = 1.2 × 36000 = Rs. 43200
Savings of Surya = 0.15 × 43200 = Rs. 6480
Quantity-I < />
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In the question, two quantities I and II are given. You have to solve both the quantities to find the correct relation between Quantity-I and Quantity-II and choose the correct option.Q. Quantity-I: A shopkeeper sold an article at 40% discount. Find the selling price of the article if its cost price and marked price are equal and there is a loss of Rs. 800 in the transaction?Quantity-II: Karthick spends 80% of his income and saves Rs. 7200. Find the savings of Surya whose income is 20% more than that of Karthick and he spends 85% of his income?a)Quantity-I > Quantity-IIb)Quantity-I c)Quantity-I ≤ Quantity-IId)Quantity-I = Quantity-II or No relatione)Quantity-I ≥ Quantity-IICorrect answer is option 'B'. Can you explain this answer?
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