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an elevator descends into a mine shaft at the rate of 6m/min. If the descent from 10m above the ground level,how long will it take to reach -350m
? Related: Summary: Integers
Most Upvoted Answer
an elevator descends into a mine shaft at the rate of 6m/min. If the d...
**Problem Analysis**
To solve this problem, we need to find the time it takes for the elevator to descend from 10m above the ground level to a depth of -350m in a mine shaft. We are given that the elevator descends at a rate of 6m/min.
**Solution**
Let's break down the problem into steps to find the solution:
1. Calculate the total distance the elevator needs to descend.
- The elevator needs to descend from 10m above the ground level to a depth of -350m. So, the total distance is 10m + 350m = 360m.
2. Calculate the time it takes for the elevator to descend.
- We are given that the elevator descends at a rate of 6m/min. So, the time it takes for the elevator to descend is the total distance divided by the descent rate:
- Time = Total distance / Descent rate
- Time = 360m / 6m/min
- Time = 60 min
3. Convert the time to hours and minutes.
- We have found that it takes 60 minutes for the elevator to descend. To express the time in hours and minutes, we can divide the total minutes by 60 to get the number of hours and take the remainder as the number of minutes:
- 60 min = 1 hour + 0 min
**Answer**
Therefore, it will take the elevator 1 hour to descend from 10m above the ground level to a depth of -350m in the mine shaft.
To solve this problem, we need to find the time it takes for the elevator to descend from 10m above the ground level to a depth of -350m in a mine shaft. We are given that the elevator descends at a rate of 6m/min.
**Solution**
Let's break down the problem into steps to find the solution:
1. Calculate the total distance the elevator needs to descend.
- The elevator needs to descend from 10m above the ground level to a depth of -350m. So, the total distance is 10m + 350m = 360m.
2. Calculate the time it takes for the elevator to descend.
- We are given that the elevator descends at a rate of 6m/min. So, the time it takes for the elevator to descend is the total distance divided by the descent rate:
- Time = Total distance / Descent rate
- Time = 360m / 6m/min
- Time = 60 min
3. Convert the time to hours and minutes.
- We have found that it takes 60 minutes for the elevator to descend. To express the time in hours and minutes, we can divide the total minutes by 60 to get the number of hours and take the remainder as the number of minutes:
- 60 min = 1 hour + 0 min
**Answer**
Therefore, it will take the elevator 1 hour to descend from 10m above the ground level to a depth of -350m in the mine shaft.
Community Answer
an elevator descends into a mine shaft at the rate of 6m/min. If the d...
TIME = DISTANCE /SPEED
TO FIND THE TOTAL DISTANCE TRAVELLED BY THE ELEVATOR, WE NEED TO ADD 350 AND 10 BECAUSE THE ELEVATOR STARTED 10m ABOVE THE GROUND LEVEL AND BEEN DEEP 350m .
THEREFORE :
DISTANCE= (350+10)m
= 360m
SPEED = 6m/min
TIME = DISTANCE/SPEED
= (360/6) minutes
= 60 minutes
ON CONVERTING 60 MINUTES TO HOUR WE GET 1 HOUR.
1 hour = 60 minutes
60 minutes= 1 hour
ANSWER : THE ELEVATOR TOOK ONE HOUR OR 60 MINUTES TO REACH THE MINE SHAFT .
TO FIND THE TOTAL DISTANCE TRAVELLED BY THE ELEVATOR, WE NEED TO ADD 350 AND 10 BECAUSE THE ELEVATOR STARTED 10m ABOVE THE GROUND LEVEL AND BEEN DEEP 350m .
THEREFORE :
DISTANCE= (350+10)m
= 360m
SPEED = 6m/min
TIME = DISTANCE/SPEED
= (360/6) minutes
= 60 minutes
ON CONVERTING 60 MINUTES TO HOUR WE GET 1 HOUR.
1 hour = 60 minutes
60 minutes= 1 hour
ANSWER : THE ELEVATOR TOOK ONE HOUR OR 60 MINUTES TO REACH THE MINE SHAFT .
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an elevator descends into a mine shaft at the rate of 6m/min. If the descent from 10m above the ground level,how long will it take to reach -350m Related: Summary: Integers?
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an elevator descends into a mine shaft at the rate of 6m/min. If the descent from 10m above the ground level,how long will it take to reach -350m Related: Summary: Integers? for Class 7 2024 is part of Class 7 preparation. The Question and answers have been prepared according to the Class 7 exam syllabus. Information about an elevator descends into a mine shaft at the rate of 6m/min. If the descent from 10m above the ground level,how long will it take to reach -350m Related: Summary: Integers? covers all topics & solutions for Class 7 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for an elevator descends into a mine shaft at the rate of 6m/min. If the descent from 10m above the ground level,how long will it take to reach -350m Related: Summary: Integers?.
an elevator descends into a mine shaft at the rate of 6m/min. If the descent from 10m above the ground level,how long will it take to reach -350m Related: Summary: Integers? for Class 7 2024 is part of Class 7 preparation. The Question and answers have been prepared according to the Class 7 exam syllabus. Information about an elevator descends into a mine shaft at the rate of 6m/min. If the descent from 10m above the ground level,how long will it take to reach -350m Related: Summary: Integers? covers all topics & solutions for Class 7 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for an elevator descends into a mine shaft at the rate of 6m/min. If the descent from 10m above the ground level,how long will it take to reach -350m Related: Summary: Integers?.
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