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In the figure shown below, AB is the diameter of the circle with centre O. CE and AB when extended meet at D. If AB = 10 units, ED = 5 units and EDB = 30°, what is the measure of CEA?
  • a)
    15°
  • b)
    30°
  • c)
    45°
  • d)
    60°
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In the figure shown below, AB is the diameter of the circle with cent...
Diameter = AB = 10 units =>Radius = OA = OE = OB = 5 units
In ΔOED; OE = ED = 5 units and D = 30° .so EOB = 30°
∴ m(arcEB)=30
m∠CDA=1/2{m(arcCA)−m(arcEB)}
30=1/2[m(arcCA)−30]
Solving this, we get
m(arcCA)=90
∴ m∠CEA=(½)×90=45
Hence, option 3.
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