How many necklaces can be made using at least 5 from 8 beads of differ...
To solve this problem, we need to use the concept of combinations.
Combination Formula:
The number of combinations of selecting r objects from a set of n objects is given by the formula: nCr = n! / (r!(n-r)!), where n! represents the factorial of n.
In this case, we have 8 beads of different colors, and we need to make necklaces using at least 5 beads. This means we can choose 5, 6, 7, or 8 beads.
Case 1: Choosing 5 beads:
The number of ways to choose 5 beads from 8 beads is given by 8C5 = 8! / (5!(8-5)!) = 8! / (5!3!) = (8 * 7 * 6) / (3 * 2 * 1) = 56.
Case 2: Choosing 6 beads:
The number of ways to choose 6 beads from 8 beads is given by 8C6 = 8! / (6!(8-6)!) = 8! / (6!2!) = (8 * 7) / (2 * 1) = 28.
Case 3: Choosing 7 beads:
The number of ways to choose 7 beads from 8 beads is given by 8C7 = 8! / (7!(8-7)!) = 8! / (7!1!) = 8 / 1 = 8.
Case 4: Choosing 8 beads:
The number of ways to choose all 8 beads from 8 beads is given by 8C8 = 8! / (8!(8-8)!) = 8! / (8!0!) = 1.
Total number of necklaces:
To get the total number of necklaces, we need to sum up the number of combinations from all the cases:
56 + 28 + 8 + 1 = 93.
Therefore, the correct answer is option 'B' which is 93.
How many necklaces can be made using at least 5 from 8 beads of differ...
The correct answer is 2952 .
the solution is simple !!!
At least 5 from 8 means we have 5,6,7, and 8.
for necklace or circle we take (n-1)!, then
4!+5!+6!+7!= 5904.
For necklace we have pairs (mirror), so we divide on 2.
5904/2= 2952