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A car travelling at a speed of 10 mps stops in 4 sec after the application of brake. If we assume the reatardation to be constant. Draw a speed time graph for the above information. Find the retardation. Find the distance
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A car travelling at a speed of 10 mps stops in 4 sec after the applica...
Applying the basic equations of kinematics in one dimension for uniform acceleration:

u = 10 m/s^2 . v = 0. t = 4 s.

b) a = (v - u)/ t = (0 - 10)/4 = -2.5 m/s^2 

c) s = u t + 1/2 a t^2 = 10 *4 - 1/2 * 2.5 * 4^2 = 20 m

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A car travelling at a speed of 10 mps stops in 4 sec after the applica...
Speed-Time Graph:
To draw the speed-time graph for the given information, we need to plot the speed on the y-axis and the time on the x-axis. Since the car is initially traveling at a speed of 10 m/s and comes to a stop in 4 seconds, the graph will consist of a straight line with a negative slope.

Retardation Calculation:
Using the formula:
Retardation (a) = Change in Velocity / Time Taken

The change in velocity is given by:
Change in Velocity = Final Velocity - Initial Velocity
= 0 - 10
= -10 m/s

The time taken is given as 4 seconds.

Therefore, the retardation can be calculated as:
Retardation (a) = -10 / 4
= -2.5 m/s²

Distance Calculation:
To calculate the distance traveled by the car, we can use the formula:
Distance (s) = (Initial Velocity * Time Taken) + (0.5 * Retardation * Time Taken²)

Plugging in the values:
Initial Velocity = 10 m/s
Time Taken = 4 seconds
Retardation = -2.5 m/s²

Distance (s) = (10 * 4) + (0.5 * -2.5 * 4²)
= 40 + (-10)
= 30 meters

Explanation:
- The speed-time graph represents the relationship between the speed of the car and the time it takes to stop.
- The graph starts at a speed of 10 m/s and gradually decreases with a constant negative slope until it reaches 0 m/s after 4 seconds.
- The negative slope indicates the deceleration or retardation of the car.
- The calculated retardation is -2.5 m/s², which means the car is slowing down at a rate of 2.5 meters per second squared.
- The distance traveled by the car during the braking process is 30 meters. This distance can be calculated using the formula mentioned above.
- The negative sign in the retardation and change in velocity indicates that the car is slowing down or decelerating.

Overall, the speed-time graph and calculations demonstrate how the car gradually slows down and comes to a stop within a given time frame, covering a certain distance during the process.
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A car travelling at a speed of 10 mps stops in 4 sec after the application of brake. If we assume the reatardation to be constant. Draw a speed time graph for the above information. Find the retardation. Find the distance
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A car travelling at a speed of 10 mps stops in 4 sec after the application of brake. If we assume the reatardation to be constant. Draw a speed time graph for the above information. Find the retardation. Find the distance for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car travelling at a speed of 10 mps stops in 4 sec after the application of brake. If we assume the reatardation to be constant. Draw a speed time graph for the above information. Find the retardation. Find the distance covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car travelling at a speed of 10 mps stops in 4 sec after the application of brake. If we assume the reatardation to be constant. Draw a speed time graph for the above information. Find the retardation. Find the distance.
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