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Calculate the mass of Sodium Acetate ch3coo NH required to make 500 ml of 0.375 molar aqueous solution molar mass of Sodium Acetate is 82.024 5 gram mole?
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Calculate the mass of Sodium Acetate ch3coo NH required to make 500 ml...
To calculate the mass of Sodium Acetate required to make a 0.375 molar aqueous solution, we need to follow a few steps:

Step 1: Understand the problem
We are given the molar mass of Sodium Acetate (82.0245 g/mol) and the desired volume of the solution (500 mL). We also know that the desired concentration is 0.375 M.

Step 2: Convert the volume to liters
Since the molar concentration is given in moles per liter (M), we need to convert the volume from milliliters (mL) to liters (L) to match the unit of concentration. We divide the volume by 1000 to convert it to liters:
500 mL ÷ 1000 = 0.5 L

Step 3: Calculate the number of moles
The molar concentration (M) is defined as moles of solute per liter of solution. We can rearrange this equation to solve for the moles of solute:
moles = concentration × volume
moles = 0.375 M × 0.5 L
moles = 0.1875 mol

Step 4: Calculate the mass of Sodium Acetate
To calculate the mass of Sodium Acetate required, we multiply the number of moles by the molar mass of Sodium Acetate:
mass = moles × molar mass
mass = 0.1875 mol × 82.0245 g/mol
mass ≈ 15.38 g

Therefore, approximately 15.38 grams of Sodium Acetate is required to make 500 mL of 0.375 molar aqueous solution.
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Calculate the mass of Sodium Acetate ch3coo NH required to make 500 ml of 0.375 molar aqueous solution molar mass of Sodium Acetate is 82.024 5 gram mole?
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