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A vessel is full of a mixture of methanol and ethanol in which there is 20% ethanol. 10 litres of mixture are drawn off and filled with methanol. If the ethanol is now 15%, what is the capacity of the vessel?
  • a)
    40l
  • b)
    30l
  • c)
    50l
  • d)
    36l
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A vessel is full of a mixture of methanol and ethanol in which there ...
Problem:
A vessel is full of a mixture of methanol and ethanol in which there is 20% ethanol. 10 litres of mixture are drawn off and filled with methanol. If the ethanol is now 15%, what is the capacity of the vessel?

Solution:
Let us assume that the vessel has a capacity of x liters.

Initial Mixture:
Initially, the mixture in the vessel contains 20% ethanol.
So, the amount of ethanol in the initial mixture = (20/100) * x = 0.2x liters.
And, the amount of methanol in the initial mixture = (80/100) * x = 0.8x liters.

When 10 liters of the initial mixture is drawn off, the amount of ethanol and methanol in the mixture will be:

Ethanol: (20/100) * 10 = 2 liters
Methanol: (80/100) * 10 = 8 liters

After drawing off 10 liters of the mixture, the vessel contains (x - 10) liters of the initial mixture.

Now, 10 liters of methanol is added to the mixture. So, the amount of methanol in the mixture will be:

Methanol: 8 + 10 = 18 liters

And, the amount of ethanol in the mixture will remain the same, i.e., 2 liters.

Final Mixture:
The final mixture contains 15% ethanol.
So, the amount of ethanol in the final mixture = (15/100) * x liters.
And, the amount of methanol in the final mixture = (85/100) * x liters.

We know that the amount of ethanol in the final mixture is (amount of ethanol in the initial mixture - 10 + 0) liters.

So, we can write the equation:

(15/100) * x = 0.2x - 10

Solving this equation, we get:

x = 40 liters

Therefore, the capacity of the vessel is 40 liters.

Answer: (a) 40 liters
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Community Answer
A vessel is full of a mixture of methanol and ethanol in which there ...
Therefore, Mixture: Methanol = 3:1
So, for 10 litres of methanol, 30 I of Mixture is needed. So, total capacity = (30 + 10)l = 40l
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