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Three circles of the same radius R are drawn so that each touches the other two. A fourth smaller circle of radius r is drawn in the gap of the other three so that it touches all of them. Then r : R is nearly equal to
  • a)
    0.155
  • b)
    0.173
  • c)
    0.224
  • d)
    0.109
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Three circles of the same radius R are drawn so that each touches the...
Let Median = Altitude =L
Above triangle will be equilateral triangle with sides of length 2R
Area of equilateral triangle
Area of an isosceles triangle
Area of Equilateral triangle = Area of 3 Isosceles triangles.
Solving, we get
p = 0.155
Answer is (a).
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Three circles of the same radius R are drawn so that each touches the other two. A fourth smaller circle of radius r is drawn in the gap of the other three so that it touches all of them. Then r : R is nearly equal toa)0.155b)0.173c)0.224d)0.109Correct answer is option 'A'. Can you explain this answer?
Question Description
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