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If p:q is the sub-duplicate ratio of p-x^2:q-x^2 then x^2 is?
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If p:q is the sub-duplicate ratio of p-x^2:q-x^2 then x^2 is?
Explanation:

To solve the given problem, we need to use the concept of sub-duplicate ratio.

Definition:

When the ratio of two quantities is such that the first is the square of the second, then the ratio is called sub-duplicate ratio.

Step-by-Step Solution:

Let us assume that p:q is the sub-duplicate ratio of p-x^2:q-x^2. We can write this as:

p:q = (p-x^2):(q-x^2)

Now, we need to simplify this equation to find x^2.

Step 1:

First, we can cross-multiply to get:

p(q-x^2) = q(p-x^2)

(pq - px2) = (pq - qx2)


Step 2:

Next, we can simplify this equation by expanding the brackets:

pq - px2 = pq - qx2


- px2 = - qx2


x2 = q/p * x2


Step 3:

Finally, we can cancel x^2 from both sides to get:

1 = q/p


q = p


Therefore, the sub-duplicate ratio of p:q is p:p or 1:1.

And, x^2 = q/p * x^2 = 1 * x^2 = x^2.

Answer:

Hence, x^2 is equal to x^2.
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If p:q is the sub-duplicate ratio of p-x^2:q-x^2 then x^2 is?
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