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A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the current in the circuit.
- a)2.2 A
- b)4.2 A
- c)6.2 A
- d)8.2 A
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A resistance of 7 ohm is connected in series with an inductance of 31....
Given: Resistance (R) = 7 ohm, Inductance (L) = 31.8mH = 0.0318 H, Voltage (V) = 100V, Frequency (f) = 50Hz
Formula used: Impedance of the circuit (Z) = √(R² + Xl²), where Xl = 2πfL (inductive reactance)
Calculation:
- Xl = 2πfL = 2π*50*0.0318 = 10 ohm (inductive reactance)
- Z = √(R² + Xl²) = √(7² + 10²) = 12.2 ohm (impedance)
- Current (I) = V/Z = 100/12.2 = 8.2 A (ampere)
Therefore, the current in the circuit is 8.2 A. Hence, option D is the correct answer.
Formula used: Impedance of the circuit (Z) = √(R² + Xl²), where Xl = 2πfL (inductive reactance)
Calculation:
- Xl = 2πfL = 2π*50*0.0318 = 10 ohm (inductive reactance)
- Z = √(R² + Xl²) = √(7² + 10²) = 12.2 ohm (impedance)
- Current (I) = V/Z = 100/12.2 = 8.2 A (ampere)
Therefore, the current in the circuit is 8.2 A. Hence, option D is the correct answer.
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Community Answer
A resistance of 7 ohm is connected in series with an inductance of 31....
XL = 2*π*f*L = 10 ohm
Z2 = (R2+XL2)
Therefore the total impedance
Z = 12.2 ohm
V = IZ
therefore,
I= V/Z = 100/12.2 = 8.2A
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A resistance of 7 ohm is connected in series with an inductance of 31.8mH. The circuit is connected to a 100V 50Hz sinusoidal supply. Calculate the current in the circuit.a)2.2 Ab)4.2 Ac)6.2 Ad)8.2 ACorrect answer is option 'D'. Can you explain this answer?
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