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A person has 10 friends of whom six are relatives .if he invite five guests such that three of them are his relatives then the total number of ways in which he can invite them are?
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A person has 10 friends of whom six are relatives .if he invite five g...
Solution:

Given:
- A person has 10 friends of whom six are relatives
- He wants to invite 5 guests such that 3 of them are his relatives.

To find: Total number of ways in which he can invite them.

We can solve this problem using combinations, which is a technique used in probability theory and combinatorics.

Combinations:

Combinations are the ways of selecting objects from a set without regard to the order of the objects. In other words, combinations are the ways of selecting a subset of objects from a larger set.

The formula for combinations is:

nCr = n!/(r!(n-r)!)

Where,
n = total number of objects
r = number of objects to be selected
! = factorial (product of all positive integers up to that number)

Steps to solve the problem:

Step 1: Finding the number of ways to select 3 relatives from 6 relatives
- Here, the person has 6 relatives and he wants to invite 3 of them.
- So, the number of ways to select 3 relatives from 6 relatives is given by 6C3.
- Using the formula, 6C3 = 6!/(3!(6-3)!) = 20.

Step 2: Finding the number of ways to select 2 non-relatives from 4 non-relatives
- Here, the person has 10 friends of whom 6 are relatives. So, he has 4 non-relatives.
- He wants to invite 5 guests such that 3 of them are his relatives. So, he needs to select 2 non-relatives from 4 non-relatives.
- The number of ways to select 2 non-relatives from 4 non-relatives is given by 4C2.
- Using the formula, 4C2 = 4!/(2!(4-2)!) = 6.

Step 3: Finding the total number of ways to invite 5 guests with 3 relatives and 2 non-relatives
- From Step 1, we know that there are 20 ways to select 3 relatives from 6 relatives.
- From Step 2, we know that there are 6 ways to select 2 non-relatives from 4 non-relatives.
- To find the total number of ways to invite 5 guests with 3 relatives and 2 non-relatives, we need to multiply the number of ways to select 3 relatives with the number of ways to select 2 non-relatives.
- So, the total number of ways to invite 5 guests with 3 relatives and 2 non-relatives is given by 20 * 6 = 120.

Therefore, the person can invite 5 guests with 3 relatives and 2 non-relatives in 120 ways.
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A person has 10 friends of whom six are relatives .if he invite five guests such that three of them are his relatives then the total number of ways in which he can invite them are?
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A person has 10 friends of whom six are relatives .if he invite five guests such that three of them are his relatives then the total number of ways in which he can invite them are? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about A person has 10 friends of whom six are relatives .if he invite five guests such that three of them are his relatives then the total number of ways in which he can invite them are? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A person has 10 friends of whom six are relatives .if he invite five guests such that three of them are his relatives then the total number of ways in which he can invite them are?.
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