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Increasing the height of a cone by 9 units increases its volume by x cubic units. Increasing its radius by 6 units also increases its volume by x cubic units. If the original height is 3 units, then the original radius is _____.
  • a)
    6 units
  • b)
    7 units
  • c)
    8 units
  • d)
    9 units
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Increasing the height of a cone by 9 units increases its volume by x c...
To solve this problem, we need to use the formulas for the volume of a cone and the relationship between the volume and the radius and height of the cone.

Let's start by calculating the original volume of the cone. The volume of a cone is given by the formula:

V = (1/3)πr^2h

Where V is the volume, π is a constant (approximately 3.14), r is the radius, and h is the height.

Let's assume the original radius of the cone is r units. Using the given height of 3 units, the original volume can be written as:

V1 = (1/3)πr^2(3)

Now, let's consider the first scenario where the height is increased by 9 units. The new height would be (3 + 9) = 12 units. The new volume can be calculated as:

V2 = (1/3)πr^2(12)

Since the increase in height of 9 units increases the volume by x cubic units, we can write:

V2 - V1 = x

Substituting the values of V1 and V2, we get:

(1/3)πr^2(12) - (1/3)πr^2(3) = x

Simplifying further:

(1/3)πr^2(12 - 3) = x

(1/3)πr^2(9) = x

Now, let's consider the second scenario where the radius is increased by 6 units. The new radius would be (r + 6) units. The new volume can be calculated as:

V3 = (1/3)π(r + 6)^2(3)

Similarly, we can write:

V3 - V1 = x

Substituting the values of V1 and V3, we get:

(1/3)π(r + 6)^2(3) - (1/3)πr^2(3) = x

Simplifying further:

(1/3)π(r^2 + 12r + 36 - r^2) = x

(1/3)π(12r + 36) = x

Since we have the same value for x in both scenarios, we can equate the expressions for x:

(1/3)πr^2(9) = (1/3)π(12r + 36)

Simplifying further:

r^2(9) = 12r + 36

9r^2 - 12r - 36 = 0

Dividing the equation by 3:

3r^2 - 4r - 12 = 0

Factoring the quadratic equation:

(3r + 2)(r - 6) = 0

Setting each factor equal to zero:

3r + 2 = 0 or r - 6 = 0

Solving for r, we get:

r = -2/3 or r = 6

Since the radius cannot be negative, the original radius of the cone is 6 units. Therefore, the correct answer is option A) 6 units.
Free Test
Community Answer
Increasing the height of a cone by 9 units increases its volume by x c...
Let the initial volume of the cone be

After increasing the radius by 6 units, new volume 


After increasing the height by 9 units, new volume


By putting the value of x in equation (i), we get:

9r2 = h[36 + 12r]
By putting the value of h in above equation, we get: 
9r2 = 3[36 + 12r]
3r2 - 12r - 36 = 0
r2 - 4r - 12 = 0
r2 - 6r + 2r - 12 = 0
r = 6 units
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Increasing the height of a cone by 9 units increases its volume by x cubic units. Increasing its radius by 6 units also increases its volume by x cubic units. If the original height is 3 units, then the original radius is _____.a)6 unitsb)7 unitsc)8 unitsd)9 unitsCorrect answer is option 'A'. Can you explain this answer?
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