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If d be the diameter of MS or tor steel bars in mm, the standard weight (in kg) per metre of thebar is
- a)0.00618 d2
- b)0.00618 d
- c)0.00816 d2
- d)0.00816 d
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If d be the diameter of MS or tor steel bars in mm, the standard weigh...
Explanation:
The weight of a steel bar per unit length is directly proportional to the square of its diameter.
Let the diameter of the steel bar be d mm.
The formula for calculating the weight of a steel bar per unit length is given by:
Weight per metre = (d^2/162) x L, where L is the length of the steel bar in meters.
Here, the factor 162 is derived as follows:
- The density of steel is 7850 kg/m^3.
- The cross-sectional area of a steel bar of diameter d is (π/4) x d^2.
- Therefore, the weight of a steel bar of length 1 meter is given by:
Weight = density x volume = 7850 x [(π/4) x d^2] x 1 = (3.14 x d^2 x 7850)/4
- Dividing both sides by 1000 to convert the weight to kilograms, we get:
Weight per metre = (3.14 x d^2 x 7850)/(4 x 1000) = (d^2 x 0.006162) kg/m
- Rounding off to four decimal places, we get:
Weight per metre = 0.00618 d^2 kg/m
Therefore, the correct answer is option A: 0.00618 d^2 kg/m.
The weight of a steel bar per unit length is directly proportional to the square of its diameter.
Let the diameter of the steel bar be d mm.
The formula for calculating the weight of a steel bar per unit length is given by:
Weight per metre = (d^2/162) x L, where L is the length of the steel bar in meters.
Here, the factor 162 is derived as follows:
- The density of steel is 7850 kg/m^3.
- The cross-sectional area of a steel bar of diameter d is (π/4) x d^2.
- Therefore, the weight of a steel bar of length 1 meter is given by:
Weight = density x volume = 7850 x [(π/4) x d^2] x 1 = (3.14 x d^2 x 7850)/4
- Dividing both sides by 1000 to convert the weight to kilograms, we get:
Weight per metre = (3.14 x d^2 x 7850)/(4 x 1000) = (d^2 x 0.006162) kg/m
- Rounding off to four decimal places, we get:
Weight per metre = 0.00618 d^2 kg/m
Therefore, the correct answer is option A: 0.00618 d^2 kg/m.
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