Mathematics Exam  >  Mathematics Questions  >  If the roots m1and m2of the auxiliary equatio... Start Learning for Free
If the roots m1 and m2 of the auxiliary equation corresponding to the given differential equation  are of the type α + iβ and α - iβ respectively, then the general solution of tne differential equation is given by 
  • a)
    y = eαx [c1 cos βx + csin βx]
  • b)
    y = eβx [c1 sin αx + ccos βx]
  • c)
    y = e-βx [c1 cos αx + csin αx]
  • d)
    y = eαx [ceβx + c2e-βx]
Correct answer is option 'A'. Can you explain this answer?
Explore Courses for Mathematics exam
If the roots m1and m2of the auxiliary equation corresponding to the given differential equationare of the type α +iβandα -iβ respectively, then the general solution of tne differential equation is given bya)y = eαx[c1cos βx + c2sin βx]b)y = eβx[c1sin αx + c2cos βx]c)y = e-βx[c1cos αx + c2sin αx]d)y = eαx[c1eβx + c2e-βx]Correct answer is option 'A'. Can you explain this answer?
Question Description
If the roots m1and m2of the auxiliary equation corresponding to the given differential equationare of the type α +iβandα -iβ respectively, then the general solution of tne differential equation is given bya)y = eαx[c1cos βx + c2sin βx]b)y = eβx[c1sin αx + c2cos βx]c)y = e-βx[c1cos αx + c2sin αx]d)y = eαx[c1eβx + c2e-βx]Correct answer is option 'A'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about If the roots m1and m2of the auxiliary equation corresponding to the given differential equationare of the type α +iβandα -iβ respectively, then the general solution of tne differential equation is given bya)y = eαx[c1cos βx + c2sin βx]b)y = eβx[c1sin αx + c2cos βx]c)y = e-βx[c1cos αx + c2sin αx]d)y = eαx[c1eβx + c2e-βx]Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the roots m1and m2of the auxiliary equation corresponding to the given differential equationare of the type α +iβandα -iβ respectively, then the general solution of tne differential equation is given bya)y = eαx[c1cos βx + c2sin βx]b)y = eβx[c1sin αx + c2cos βx]c)y = e-βx[c1cos αx + c2sin αx]d)y = eαx[c1eβx + c2e-βx]Correct answer is option 'A'. Can you explain this answer?.
Solutions for If the roots m1and m2of the auxiliary equation corresponding to the given differential equationare of the type α +iβandα -iβ respectively, then the general solution of tne differential equation is given bya)y = eαx[c1cos βx + c2sin βx]b)y = eβx[c1sin αx + c2cos βx]c)y = e-βx[c1cos αx + c2sin αx]d)y = eαx[c1eβx + c2e-βx]Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mathematics. Download more important topics, notes, lectures and mock test series for Mathematics Exam by signing up for free.
Here you can find the meaning of If the roots m1and m2of the auxiliary equation corresponding to the given differential equationare of the type α +iβandα -iβ respectively, then the general solution of tne differential equation is given bya)y = eαx[c1cos βx + c2sin βx]b)y = eβx[c1sin αx + c2cos βx]c)y = e-βx[c1cos αx + c2sin αx]d)y = eαx[c1eβx + c2e-βx]Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of If the roots m1and m2of the auxiliary equation corresponding to the given differential equationare of the type α +iβandα -iβ respectively, then the general solution of tne differential equation is given bya)y = eαx[c1cos βx + c2sin βx]b)y = eβx[c1sin αx + c2cos βx]c)y = e-βx[c1cos αx + c2sin αx]d)y = eαx[c1eβx + c2e-βx]Correct answer is option 'A'. Can you explain this answer?, a detailed solution for If the roots m1and m2of the auxiliary equation corresponding to the given differential equationare of the type α +iβandα -iβ respectively, then the general solution of tne differential equation is given bya)y = eαx[c1cos βx + c2sin βx]b)y = eβx[c1sin αx + c2cos βx]c)y = e-βx[c1cos αx + c2sin αx]d)y = eαx[c1eβx + c2e-βx]Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of If the roots m1and m2of the auxiliary equation corresponding to the given differential equationare of the type α +iβandα -iβ respectively, then the general solution of tne differential equation is given bya)y = eαx[c1cos βx + c2sin βx]b)y = eβx[c1sin αx + c2cos βx]c)y = e-βx[c1cos αx + c2sin αx]d)y = eαx[c1eβx + c2e-βx]Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice If the roots m1and m2of the auxiliary equation corresponding to the given differential equationare of the type α +iβandα -iβ respectively, then the general solution of tne differential equation is given bya)y = eαx[c1cos βx + c2sin βx]b)y = eβx[c1sin αx + c2cos βx]c)y = e-βx[c1cos αx + c2sin αx]d)y = eαx[c1eβx + c2e-βx]Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Mathematics tests.
Explore Courses for Mathematics exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev