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The Residue of for z = ia is
  • a)
    1/4α3
  • b)
    −i/4α3
  • c)
    −1/4α3
  • d)
    i/4α3
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The Residue offor z = ia isa)1/4α3b)−i/4α3c)−1...
Cauchy's Residue Theorem:
Residue of f(z):
Residue of f(z) is denoted as Res[f(z) : z = z0]
z0 is a simple pole of the function f(z)
If f(z) = p(z) / q(z)
Where, p(z), q(z) are polynomials
Then residue is,
Res[f(z) : z = z0] = 
If f(z) has a pole of order 'm' at z = z0 then
Res [f(z) : z = z0] =
Calculation:
Given,

Pole of f(z) has order "2" 

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Community Answer
The Residue offor z = ia isa)1/4α3b)−i/4α3c)−1...
Cauchy's Residue Theorem:
Residue of f(z):
Residue of f(z) is denoted as Res[f(z) : z = z0]
z0 is a simple pole of the function f(z)
If f(z) = p(z) / q(z)
Where, p(z), q(z) are polynomials
Then residue is,
Res[f(z) : z = z0] = 
If f(z) has a pole of order 'm' at z = z0 then
Res [f(z) : z = z0] =
Calculation:
Given,

Pole of f(z) has order "2" 

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The Residue offor z = ia isa)1/4α3b)−i/4α3c)−1/4α3d)i/4α3Correct answer is option 'B'. Can you explain this answer?
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