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Integration of the complex function f (z) =  in the counterclockwise direction, around |z – 1| = 1, is
  • a)
    -πi
  • b)
    0
  • c)
    πi
  • d)
    2πi
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Integration of the complex function f (z) = in the counterclockwise di...
Concept:
Cauchy’s Theorem:
If f(z) is an analytic function and f’(z) is continuous at each point within and on a closed curve C, then
Cauchy’s Integral Formula:
If f(z) is an analytic function within a closed curve and if a is any point within C, then

Residue Theorem:
If f(z) is analytic in a closed curve C except at a finite number of singular points within C, then
 = 2πi × [sum of residues at the singualr points with in C]
Formula to find residue:
1. If f(z) has a simple pole at z = a, then

2. If f(z) has a pole of order n at z = a, then

Application:
Given function is 
Poles: z = 1, -1
|z – 1| = 1
⇒ |x – 1 + iy| = 1

The given region is a circle with the centre at (1, 0) and the radius is 1.
Only pole z = 1, lies within the given region.
Residue at z = 1 is,  
The value of the integral = 2πi × 0.5 = πi
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Most Upvoted Answer
Integration of the complex function f (z) = in the counterclockwise di...
Concept:
Cauchy’s Theorem:
If f(z) is an analytic function and f’(z) is continuous at each point within and on a closed curve C, then
Cauchy’s Integral Formula:
If f(z) is an analytic function within a closed curve and if a is any point within C, then

Residue Theorem:
If f(z) is analytic in a closed curve C except at a finite number of singular points within C, then
 = 2πi × [sum of residues at the singualr points with in C]
Formula to find residue:
1. If f(z) has a simple pole at z = a, then

2. If f(z) has a pole of order n at z = a, then

Application:
Given function is 
Poles: z = 1, -1
|z – 1| = 1
⇒ |x – 1 + iy| = 1

The given region is a circle with the centre at (1, 0) and the radius is 1.
Only pole z = 1, lies within the given region.
Residue at z = 1 is,  
The value of the integral = 2πi × 0.5 = πi
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Integration of the complex function f (z) = in the counterclockwise direction, around |z – 1| = 1, isa)-πib)0c)πid)2πiCorrect answer is option 'C'. Can you explain this answer?
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