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where c is the upper half of the circle |z| = 1.- a)-2/3
- b)2/3
- c)3/2
- d)-3/2
Correct answer is option 'B'. Can you explain this answer?
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where c is the upper half of the circle |z| = 1.a)-2/3b)2/3c)3/2d)-3/2...
Given counter c is the circle, |z| = 1
⇒ z = eiθ ⇒ dz = ieiθdθ
Now, for upper half of the circle, 0 ≤ θ ≤ π
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where c is the upper half of the circle |z| = 1.a)-2/3b)2/3c)3/2d)-3/2...
Given counter c is the circle, |z| = 1
⇒ z = eiθ ⇒ dz = ieiθdθ
Now, for upper half of the circle, 0 ≤ θ ≤ π
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where c is the upper half of the circle |z| = 1.a)-2/3b)2/3c)3/2d)-3/2Correct answer is option 'B'. Can you explain this answer?
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