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The complete solution of the linear differential equation
- a)c1 e-pt + c2 e-qt
- b)c1 ept - c2 eqt
- c)c1 e-pt + c2 eqt
- d)c1 ept + c2 eqt
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The complete solution of the linear differential equationa)c1e-pt+ c2e...
For the given differential equation:
(D2 + (p + q)D + pq)z = 0
⇒ f(D)z = 0
Where f(D) = D2 + (p + q)D + pq
Consider in terms of M ⇒ f(m) = 0
M2 + (p + q)m + pq = 0
M1 = -q & m2 = -p
M1 = -q & m2 = -p
Hence, its solution is
Z = C1e-pt + C2e-qt
∴ Complete solution of the linear differential equation
is c1 e-pt + c2 e-qt
is c1 e-pt + c2 e-qt
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