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The directional derivative of f(x, y, z) = xyz at point (-1, 1, 3) in the direction of vector î - 2ĵ + 2k̂ is
  • a)
    3î - 3ĵ - k̂
  • b)
    −7/3
  • c)
    7/3
  • d)
    7
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The directional derivative of f(x, y, z) = xyz at point (-1, 1, 3) in ...
Concept:
Directional Derivative = Gradient of function × Unit direction Vector
If F = f(x, y, z) then,
For the given direction vector
Unit direction vector = 
and 
Calculation:
Given, f(x,y,z) = xyz
∴ (Grad f)P = 
Direction vector 
Unit direction vector
∴ Directional Derivative = 
D. D = 
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Community Answer
The directional derivative of f(x, y, z) = xyz at point (-1, 1, 3) in ...

Calculating the Directional Derivative:

To calculate the directional derivative of the function \( f(x, y, z) = xyz \) at the point (-1, 1, 3) in the direction of the vector \( \textbf{i} - 2\textbf{j} + 2\textbf{k} \), we follow these steps:

1. Find the Gradient of the Function:
The gradient of a function is given by the vector \( \nabla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z} \right) \).
For the function \( f(x, y, z) = xyz \), the gradient is \( \nabla f = \left( yz, xz, xy \right) \).

2. Compute the Gradient at the Given Point:
Substitute the values of x, y, and z from the given point (-1, 1, 3) into the gradient vector to get \( \nabla f = \left( 1 \times 3, -1 \times 3, -1 \times 1 \right) = (3, -3, -1) \).

3. Normalize the Direction Vector:
Normalize the given direction vector \( \textbf{v} = \textbf{i} - 2\textbf{j} + 2\textbf{k} \) to get a unit vector \( \textbf{u} \) in the same direction.

4. Calculate the Directional Derivative:
The directional derivative is given by the dot product of the gradient and the unit direction vector:
\( D_{\textbf{u}} f = \nabla f \cdot \textbf{u} = (3, -3, -1) \cdot \left( \frac{1}{3}, -\frac{2}{3}, \frac{2}{3} \right) = 7/3 \).

Therefore, the directional derivative of \( f(x, y, z) = xyz \) at point (-1, 1, 3) in the direction of the vector \( \textbf{i} - 2\textbf{j} + 2\textbf{k} \) is \( 7/3 \) (option C).
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The directional derivative of f(x, y, z) = xyz at point (-1, 1, 3) in the direction of vector i - 2j + 2k isa)3i - 3j - kb)−7/3c)7/3d)7Correct answer is option 'C'. Can you explain this answer?
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