If x is real, find the minimum value of 4x2 - 5x + 1 = 0a)0b)1c)9/16d)-9/16Correct answer is option 'D'. Can you explain this answer?

Question

Answer

Given:

We have the given expression 4x² - 5x + 1 = 0

Concept used:

The minimum value of any quadratic expression ax² + bx + c = 0, (when a > 0) is -D/4a

Where, D = b² - 4ac

Calculation:

Here, a, b and c is 4, -5 and 1 respectively

So, D = (-5)² - (4 × 4 × 1)

⇒ 25 - 16

⇒ 9

So, minimum value = (-9)/(4 × 4)

⇒ (-9)/16

∴ The minimum value of given expression is -9/16.