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In the circuit shown below, steady state was reached when the switch ‘s’ was open. The switch was closed at t = 0. Then initial value of the current through the capacitor 2C is?
  • a)
    0 A
  • b)
    1 A
  • c)
    2 A
  • d)
    3 A
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In the circuit shown below, steady state was reached when the switch &...
At steady-state conditions, the capacitor acts as an open circuit, and the inductor acts as a short circuit.
Now considering t = 0-,
Now voltage across 4 Ω resistor is 12 V.
Considering t = 0+
By KCL, 
i2c (0+) = 2 A
The initial value of the current through the capacitor 2 C is 2 A.
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Most Upvoted Answer
In the circuit shown below, steady state was reached when the switch &...
At steady-state conditions, the capacitor acts as an open circuit, and the inductor acts as a short circuit.
Now considering t = 0-,
Now voltage across 4 Ω resistor is 12 V.
Considering t = 0+
By KCL, 
i2c (0+) = 2 A
The initial value of the current through the capacitor 2 C is 2 A.
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