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The transfer function of the system is G(s) = 100/(s + 1) (s + 100). For a unit step input to the system the approximate settling time for 2% criterion is:
  • a)
    100 sec
  • b)
    4 sec
  • c)
    1 sec
  • d)
    0.01 sec
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The transfer function of the system is G(s) = 100/(s + 1) (s + 100). F...
G(s) = 100/(s + 1) (s + 100)
Taking the dominant pole consideration,
S = -100 pole is not taken.
G(s) = 100/s + 1
Now it is first order system, ts  4T = 4 sec.
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Most Upvoted Answer
The transfer function of the system is G(s) = 100/(s + 1) (s + 100). F...
G(s) = 100/(s + 1) (s + 100)
Taking the dominant pole consideration,
S = -100 pole is not taken.
G(s) = 100/s + 1
Now it is first order system, ts  4T = 4 sec.
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Community Answer
The transfer function of the system is G(s) = 100/(s + 1) (s + 100). F...
Settling Time Calculation:

To calculate the settling time for a system with a transfer function of G(s) = 100/(s^2 + 99s), we need to first determine the poles of the system.

Finding Poles:
- The poles of the system are the values of s that make the denominator of the transfer function equal to zero.
- Setting the denominator equal to zero, we get s^2 + 99s = 0.
- Solving for s, we find that the poles are at s = 0 and s = -99.

Calculating Settling Time:
- The settling time for a second-order system with a pair of complex conjugate poles can be approximated using the formula: Ts = 4/(ζωn), where ζ is the damping ratio and ωn is the natural frequency.
- For a second-order system with complex poles, the damping ratio ζ can be calculated as: ζ = 1/(2ζ), where ζ is the real part of the pole.
- Substituting the values of the poles into the formula, we find that ζ = 1/2 and ωn = 99.
- Plugging these values into the settling time formula, we get Ts = 4/(1 * 99) = 4 seconds.

Therefore, the approximate settling time for a unit step input to the system with a transfer function of G(s) = 100/(s^2 + 99s) is 4 seconds.
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