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A series RL circuit (as shown in fig) has a constant voltage V = 60 V applied at t = 0. Determine the current flowing through the inductor.
  • a)
    (1 – e-2t)
  • b)
    2(1 – e-2t)
  • c)
    2(e2t)
  • d)
    e-2t
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A series RL circuit (as shown in fig) has a constant voltage V = 60 V ...
The expression of current in a series RL circuit is:
V = 60 V, R = 30, L = 15 H
Current through the inductor is,
⇒ I = 2(1 – e-2t)
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Most Upvoted Answer
A series RL circuit (as shown in fig) has a constant voltage V = 60 V ...
The expression of current in a series RL circuit is:
V = 60 V, R = 30, L = 15 H
Current through the inductor is,
⇒ I = 2(1 – e-2t)
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