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A capacitor having a capacitance of 20 μF is connected in series with a non-inductive resistance of 120 Ω across a 100-V, 50-Hz supply. Calculate the power.
- a)63.45 W
- b)30.20 W
- c)10.58 W
- d)58.62 W
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A capacitor having a capacitance of 20 μF is connected in series wi...
Concept:
The voltage across the resistance is given by:
vr(t) = i(t) × R
The current i(t) is given by:
Calculation:
Given, f = 50 Hz and C = 20 × 10-6 F
XC = 159.23 Ω
i(t) = 0.501 A
P = i2R
P = (0.501)2 × 120
P = 30.20 W
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Community Answer
A capacitor having a capacitance of 20 μF is connected in series wi...
Given data:
- Capacitance (C) = 20 μF
- Resistance (R) = 120 Ω
- Supply voltage (V) = 100 V
- Frequency (f) = 50 Hz
Calculating the reactance of the capacitor:
- Reactance of a capacitor (Xc) = 1 / (2πfC)
- Xc = 1 / (2 * π * 50 * 20x10^-6)
- Xc ≈ 159.15 Ω
Calculating the total impedance:
- Total impedance (Z) = √(R^2 + Xc^2)
- Z = √(120^2 + 159.15^2)
- Z ≈ 200 Ω
Calculating the current:
- Current (I) = V / Z
- I = 100 / 200
- I = 0.5 A
Calculating the power:
- Power (P) = V * I * cos(θ)
- Since the circuit consists of a non-inductive resistance, θ = 0
- Power (P) = 100 * 0.5 * 1
- Power (P) = 50 W
Therefore, the power consumed in the circuit is approximately 50 W. Hence, the correct answer is option 'B' (30.20 W).
- Capacitance (C) = 20 μF
- Resistance (R) = 120 Ω
- Supply voltage (V) = 100 V
- Frequency (f) = 50 Hz
Calculating the reactance of the capacitor:
- Reactance of a capacitor (Xc) = 1 / (2πfC)
- Xc = 1 / (2 * π * 50 * 20x10^-6)
- Xc ≈ 159.15 Ω
Calculating the total impedance:
- Total impedance (Z) = √(R^2 + Xc^2)
- Z = √(120^2 + 159.15^2)
- Z ≈ 200 Ω
Calculating the current:
- Current (I) = V / Z
- I = 100 / 200
- I = 0.5 A
Calculating the power:
- Power (P) = V * I * cos(θ)
- Since the circuit consists of a non-inductive resistance, θ = 0
- Power (P) = 100 * 0.5 * 1
- Power (P) = 50 W
Therefore, the power consumed in the circuit is approximately 50 W. Hence, the correct answer is option 'B' (30.20 W).
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A capacitor having a capacitance of 20 μF is connected in series with a non-inductive resistance of 120 Ω across a 100-V, 50-Hz supply. Calculate the power.a)63.45 Wb)30.20 Wc)10.58 Wd)58.62 WCorrect answer is option 'B'. Can you explain this answer?
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A capacitor having a capacitance of 20 μF is connected in series with a non-inductive resistance of 120 Ω across a 100-V, 50-Hz supply. Calculate the power.a)63.45 Wb)30.20 Wc)10.58 Wd)58.62 WCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A capacitor having a capacitance of 20 μF is connected in series with a non-inductive resistance of 120 Ω across a 100-V, 50-Hz supply. Calculate the power.a)63.45 Wb)30.20 Wc)10.58 Wd)58.62 WCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A capacitor having a capacitance of 20 μF is connected in series with a non-inductive resistance of 120 Ω across a 100-V, 50-Hz supply. Calculate the power.a)63.45 Wb)30.20 Wc)10.58 Wd)58.62 WCorrect answer is option 'B'. Can you explain this answer?.
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