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The peak percentage overshoot of the closed loop system is :
  • a)
    5.0%
  • b)
    10.0%
  • c)
    16.3%
  • d)
    1.63%
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The peak percentage overshoot of the closed loop system is :a)5.0%b)10...
C(s)/R(s) = 1/s2+s+1
C(s)/R(s) = w/ws+ 2Gws + w2
Compare both the equations,
w = 1 rad/sec
2Gw = 1
Mp = 16.3 %
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Community Answer
The peak percentage overshoot of the closed loop system is :a)5.0%b)10...
Understanding Peak Percentage Overshoot
Peak percentage overshoot is a crucial parameter in control systems that indicates how much a system exceeds its final steady-state value during transient response. It is often represented as a percentage of the steady-state value.
Formula for Peak Percentage Overshoot
- The peak percentage overshoot (P.O.) can be calculated using the formula:
P.O. = (Peak Value - Steady-State Value) / Steady-State Value × 100%
- This is particularly relevant for second-order systems characterized by their damping ratio (ζ) and natural frequency (ω_n).
Factors Influencing Peak Overshoot
- Damping Ratio (ζ):
- A critical factor that determines the overshoot. Higher damping ratios lead to lower overshoots.
- For ζ < 1="" (underdamped="" systems),="" overshoot="" is="" more="" />
- Natural Frequency (ω_n):
- Influences the speed of response. Higher natural frequencies can result in higher overshoot if damping is not sufficient.
Example Calculation
- For a standard underdamped second-order system, the peak percentage overshoot can be approximated as:
P.O. ≈ e^((-ζπ)/(sqrt(1-ζ^2)))
- If a system has a damping ratio of approximately 0.5, plug in the values to find that P.O. can result in around 16.3%.
Conclusion
- In this context, the correct answer of 16.3% (option 'C') suggests that the system exhibits a moderate amount of overshoot, typical for a second-order underdamped system. Understanding this helps in designing control systems to achieve desired transient characteristics while minimizing overshoot.
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