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Consider a voltage series feedback network, where amplifier gain = 100, feedback factor = 5. For the basic amplifier, input voltage = 4V, input current=2mA. Find the input resistance of the network.
- a)1.002kΩ
- b)1002kΩ
- c)2kΩ
- d)2000kΩ
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Consider a voltage series feedback network, where amplifier gain = 100...
To find the input resistance of the network, we can use the formula:
Input resistance (Rin) = (Voltage gain / Current gain) * (Feedback factor / Amplifier gain)
Given:
Amplifier gain (Av) = 100
Feedback factor (β) = 5
The voltage gain (Av) can be calculated as the ratio of output voltage (Vo) to input voltage (Vi):
Av = Vo / Vi
Since it is a voltage series feedback network, the output voltage (Vo) and input voltage (Vi) are related by the formula:
Vo = Vi / (1 + β * Av)
Substituting the given values:
Av = 100
β = 5
Vo = Vi / (1 + 5 * 100)
Vo = Vi / 501
Now, we can calculate the output voltage (Vo) using the formula:
Vo = Av * Vi
Vo = 100 * 4V
Vo = 400V
Substituting the calculated values into the equation for Vo:
400V = Vi / 501
Solving for Vi:
Vi = 400V * 501
Vi = 200,400V
Now, we can substitute the calculated values into the formula for input resistance (Rin):
Rin = (Av / Ai) * (β / Av)
Rin = (100 / (2mA / 200,400V)) * (5 / 100)
Rin = (100 / (0.002A / 200,400V)) * (5 / 100)
Rin = (100 / (0.002A / 200,400V)) * (5 / 100)
Rin = (100 / (0.002A / 200,400V)) * (5 / 100)
Rin = (100 / 0.002A) * (5 / 100)
Rin = (100 / 0.002A) * (5 / 100)
Rin = (100 / 0.002A) * (5 / 100)
Rin = (100 / 0.002A) * (5 / 100)
Rin = (100 / 0.002A) * (5 / 100)
Rin = 1,000 * 0.05
Rin = 50
Therefore, the input resistance of the network is 50 ohms.
Input resistance (Rin) = (Voltage gain / Current gain) * (Feedback factor / Amplifier gain)
Given:
Amplifier gain (Av) = 100
Feedback factor (β) = 5
The voltage gain (Av) can be calculated as the ratio of output voltage (Vo) to input voltage (Vi):
Av = Vo / Vi
Since it is a voltage series feedback network, the output voltage (Vo) and input voltage (Vi) are related by the formula:
Vo = Vi / (1 + β * Av)
Substituting the given values:
Av = 100
β = 5
Vo = Vi / (1 + 5 * 100)
Vo = Vi / 501
Now, we can calculate the output voltage (Vo) using the formula:
Vo = Av * Vi
Vo = 100 * 4V
Vo = 400V
Substituting the calculated values into the equation for Vo:
400V = Vi / 501
Solving for Vi:
Vi = 400V * 501
Vi = 200,400V
Now, we can substitute the calculated values into the formula for input resistance (Rin):
Rin = (Av / Ai) * (β / Av)
Rin = (100 / (2mA / 200,400V)) * (5 / 100)
Rin = (100 / (0.002A / 200,400V)) * (5 / 100)
Rin = (100 / (0.002A / 200,400V)) * (5 / 100)
Rin = (100 / (0.002A / 200,400V)) * (5 / 100)
Rin = (100 / 0.002A) * (5 / 100)
Rin = (100 / 0.002A) * (5 / 100)
Rin = (100 / 0.002A) * (5 / 100)
Rin = (100 / 0.002A) * (5 / 100)
Rin = (100 / 0.002A) * (5 / 100)
Rin = 1,000 * 0.05
Rin = 50
Therefore, the input resistance of the network is 50 ohms.
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Community Answer
Consider a voltage series feedback network, where amplifier gain = 100...
RI = VI/II = 4/2m = 2kΩ
RIF = RI(1+A.β) = 2k(1+500)
= 1002kΩ.
RIF = RI(1+A.β) = 2k(1+500)
= 1002kΩ.
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