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A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?
- a)38 years
- b)40 years
- c)43 years
- d)45 years
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A mother is twice as old as her son. If 20 years ago, the age of the m...
Let the age of son = X years
∴Age of mother would be =2X
As per question 20 years ago;
10 (X -20) = 2X - 20
10X - 200 = 2X - 20
10X - 2X= - 20 + 200
8X = 180
X = 180/8 = 22.5 years
∴ Age of mother = 22.5 * 2 = 45 years
∴Age of mother would be =2X
As per question 20 years ago;
10 (X -20) = 2X - 20
10X - 200 = 2X - 20
10X - 2X= - 20 + 200
8X = 180
X = 180/8 = 22.5 years
∴ Age of mother = 22.5 * 2 = 45 years
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Community Answer
A mother is twice as old as her son. If 20 years ago, the age of the m...
To solve this problem, let's assign variables to the ages of the mother and the son. Let M represent the age of the mother and S represent the age of the son.
Given information:
1. The mother is twice as old as her son: M = 2S
2. 20 years ago, the age of the mother was 10 times the age of the son: M - 20 = 10(S - 20)
Let's solve these equations to find the present age of the mother.
Solving the equations:
1. Substituting M = 2S into the second equation:
2S - 20 = 10(S - 20)
2S - 20 = 10S - 200
10S - 2S = 200 - 20
8S = 180
S = 180/8
S = 22.5
2. Substituting S = 22.5 into the first equation:
M = 2(22.5)
M = 45
Therefore, the present age of the mother is 45 years (option D).
Given information:
1. The mother is twice as old as her son: M = 2S
2. 20 years ago, the age of the mother was 10 times the age of the son: M - 20 = 10(S - 20)
Let's solve these equations to find the present age of the mother.
Solving the equations:
1. Substituting M = 2S into the second equation:
2S - 20 = 10(S - 20)
2S - 20 = 10S - 200
10S - 2S = 200 - 20
8S = 180
S = 180/8
S = 22.5
2. Substituting S = 22.5 into the first equation:
M = 2(22.5)
M = 45
Therefore, the present age of the mother is 45 years (option D).
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A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?a)38 yearsb)40 yearsc)43 yearsd)45 yearsCorrect answer is option 'D'. Can you explain this answer?
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