Full Adder Configuration

To understand the number of gates required for the configuration of a full adder, let's first discuss what a full adder is and its logical representation.

A full adder is a combinational circuit that takes in three inputs: A, B, and Cin (carry-in) and produces two outputs: Sum (S) and Cout (carry-out). It is used to add two binary numbers along with a carry input from the previous stage.

The logical representation of a full adder can be expressed using basic logic gates such as AND, OR, and EXOR gates.

Logical Representation of Full Adder

The logical representation of a full adder is as follows:

1. Sum (S) output:
- It is the output of the EXOR gate.
- It is calculated by taking the EXOR of A, B, and Cin.

2. Carry-out (Cout) output:
- It is the output of the OR gate.
- It is calculated by taking the OR of the AND gates' outputs.

Calculating the Number of Gates

Now, let's calculate the number of AND, OR, and EXOR gates required for the configuration of a full adder.

1. AND gates:
- We require 2 AND gates to calculate the carry-out (Cout) output.
- Each AND gate takes 2 inputs, so a total of 2 AND gates are needed.

2. OR gates:
- We require 1 OR gate to calculate the carry-out (Cout) output.
- The OR gate takes 2 inputs.

3. EXOR gates:
- We require 2 EXOR gates to calculate the sum (S) output.
- Each EXOR gate takes 3 inputs, so a total of 2 EXOR gates are needed.

Hence, the number of AND, OR, and EXOR gates required for the configuration of a full adder is as follows:

- AND gates: 2
- OR gates: 1
- EXOR gates: 2

Therefore, the correct answer is option 'B' (2, 1, 2).