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According to gauss theorem, the electric flux on a closed surface depends on?
- a)The area of open surface
- b)Charge enclosed
- c)Magnetic field of charge
- d)Charge outside the sphere
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
According to gauss theorem, the electric flux on a closed surface depe...
CONCEPT
- Electric Flux: It is defined as the number of electric field lines passing through the perpendicular unit area.
- Electric Flux = (Φ) = EA⊥ [E = electric field, A = perpendicular area]
- Electric flux (Φ) = EA cos θ [where θ is the angle between area plane and electric field]
- The flux is maximum when the angle is 0°
- Gauss Law: According to gauss’s law, total electric flux through a closed surface enclosing a charge is 1/ϵ0 times the magnitude of charge enclosed.
Where, Φ = electric flux, Qin = charge enclosed the sphere, ϵ0 = permittivity of space (8.85 × 10-12 C2/Nm2), dS = surface area
According to gauss’s law,
The flux of the net electric field through a closed surface equals the net charge enclosed by the surface divided by ϵ0.
Electric flux on a closed surface only depends on the enclosed charge.
∴ Option 2 is correct
Most Upvoted Answer
According to gauss theorem, the electric flux on a closed surface depe...
CONCEPT
- Electric Flux: It is defined as the number of electric field lines passing through the perpendicular unit area.
- Electric Flux = (Φ) = EA⊥ [E = electric field, A = perpendicular area]
- Electric flux (Φ) = EA cos θ [where θ is the angle between area plane and electric field]
- The flux is maximum when the angle is 0°
- Gauss Law: According to gauss’s law, total electric flux through a closed surface enclosing a charge is 1/ϵ0 times the magnitude of charge enclosed.
Where, Φ = electric flux, Qin = charge enclosed the sphere, ϵ0 = permittivity of space (8.85 × 10-12 C2/Nm2), dS = surface area
According to gauss’s law,
The flux of the net electric field through a closed surface equals the net charge enclosed by the surface divided by ϵ0.
Electric flux on a closed surface only depends on the enclosed charge.
∴ Option 2 is correct
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Community Answer
According to gauss theorem, the electric flux on a closed surface depe...
Explanation:
Electric flux on a closed surface is defined by Gauss's Law, which relates the electric flux passing through a closed surface to the charge enclosed by that surface.
Charge enclosed:
- The electric flux on a closed surface depends on the amount of charge enclosed by that surface.
- The more charge enclosed, the greater the electric flux passing through the surface.
Effect of other factors:
- The area of the open surface does not directly affect the electric flux on a closed surface. The flux depends on the charge distribution, not the size of the surface.
- The magnetic field of the charge also does not affect the electric flux. The electric flux is solely determined by the electric field produced by the charge.
Mathematical representation:
- Mathematically, Gauss's Law can be expressed as Φ = Q/ε₀, where Φ is the electric flux, Q is the charge enclosed by the surface, and ε₀ is the permittivity of free space.
Therefore, the electric flux on a closed surface depends on the charge enclosed by that surface according to Gauss's Law.
Electric flux on a closed surface is defined by Gauss's Law, which relates the electric flux passing through a closed surface to the charge enclosed by that surface.
Charge enclosed:
- The electric flux on a closed surface depends on the amount of charge enclosed by that surface.
- The more charge enclosed, the greater the electric flux passing through the surface.
Effect of other factors:
- The area of the open surface does not directly affect the electric flux on a closed surface. The flux depends on the charge distribution, not the size of the surface.
- The magnetic field of the charge also does not affect the electric flux. The electric flux is solely determined by the electric field produced by the charge.
Mathematical representation:
- Mathematically, Gauss's Law can be expressed as Φ = Q/ε₀, where Φ is the electric flux, Q is the charge enclosed by the surface, and ε₀ is the permittivity of free space.
Therefore, the electric flux on a closed surface depends on the charge enclosed by that surface according to Gauss's Law.
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According to gauss theorem, the electric flux on a closed surface depends on?a)The area of open surfaceb)Charge enclosedc)Magnetic field of charged)Charge outside the sphereCorrect answer is option 'B'. Can you explain this answer?
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