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Find the number of 2 × 1 MUX (multiplexers) required to implement 16 × 1 MUX.
- a)15
- b)20
- c)5
- d)9
Correct answer is option 'A'. Can you explain this answer?
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Find the number of 2 × 1 MUX (multiplexers) required to implemen...
To implement 2n × 1 MUX using 2 × 1 MUX, the total number of 2 × 1 MUX required is (2n - 1).
∴ The number of 2 × 1 multiplexer required to implement 16 × 1 MUX will be:
n = 16 - 1 = 15
Or we can follow the below steps to calculate the same:
1st stage = 16/2 = 8
2nd stage = 8/2 = 4
3rd stage = 4/2 = 2
4th stage = 2/2 = 1
The sum will give the total number of MUX required to implement 16 × 1 multiplexer using 2 × 1, i.e.
n = 8 + 4 + 2 + 1 = 15
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Find the number of 2 × 1 MUX (multiplexers) required to implement 16 × 1 MUX.a)15b)20c)5d)9Correct answer is option 'A'. Can you explain this answer?
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